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maw [93]
4 years ago
15

512 students and teachers attended a play in the auditorium. There were 307 teachers in attendance.

Mathematics
2 answers:
anzhelika [568]4 years ago
7 0

Answer:

60% for teachers and 40% for students

Step-by-step explanation:

Calculator lol

34kurt4 years ago
7 0

Answer:

teachers: 59.96

students: 40.03

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Wich method can you use yo decide wich of several integers has the greatest value?
serg [7]

Answer:

C

The integer with the greatest value is the one that is farthest to the right hand side of the number line

Step-by-step explanation:

The number line is constructed in a way such that we have a center point of zero with positive values to the right of the number line and negative values to the left of the number line.

Moving deeper right, we have an increase in positivity, with the more positive values rightwards, indicating an increase in the numbers to the right

Moving to the left, we have an increase in negativity, but a decrease in value. The negative numbers closer to zero are more positive and command higher values than the values which are farther from zero.

What these indicates is that the more rightward a number, the greater its value

4 0
3 years ago
Find the mode of this data set<br>18.33.25,36,35,31, 19, 30,23,28.33​
saw5 [17]

Answer:

33

Step-by-step explanation:

So I just put them in order....18,19,23,25,28,30,31,33,33,35,36

and you can see that 33 pops up twice when the others only pop up once..so the answer is 33

3 0
3 years ago
What is this limit equal to?
Nadya [2.5K]

Since the cotangent function is defined as

\cot(x) = \dfrac{\cos(x)}{\sin(x)}

we have that the cotangent equals zero at \frac{\pi}{2}, because we have

\cot\left(\dfrac{\pi}{2}\right) = \dfrac{\cos\left(\frac{\pi}{2}\right)}{\sin\left(\frac{\pi}{2}\right)} = \dfrac{0}{1} =0

So, the limit simply becomes

\dfrac{\pi}{2}\cdot 0 = 0

4 0
4 years ago
The height of a triangle is 4 in. greater than twice its base. The area of the triangle is no more than 168 in.2. Which inequali
netineya [11]

Let

x-------> the length of the base of triangle

y-------> the height of the triangle

we know that

the area of the triangle is equal to

A=\frac{1}{2}xy

in this problem we have

A \leq 168\ in^{2}

so

\frac{1}{2}xy\leq 168 --------> equation 1

y=2x+4 --------> equation 2

Substitute equation 2 in equation 1

\frac{1}{2}x[2x+4]\leq 168

x^{2}+2x \leq 168

therefore

<u>the answer is</u>

The inequality that can be used to find the possible lengths, x, of the base of the triangle is  \frac{1}{2}x[2x+4]\leq 168 or x^{2}+2x \leq 168

5 0
3 years ago
Read 2 more answers
I suck at math please help me
attashe74 [19]
-2/15 is the answer
3 0
3 years ago
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