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nadya68 [22]
3 years ago
15

Ben has a cellphone plan where he pays $12 per

Mathematics
1 answer:
Vlada [557]3 years ago
3 0

Answer:

H

Step-by-step explanation:

I have done the work before

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I'm sorry, but I'm a bit confused on what you're trying to ask. Could you please clarify? 
4 0
3 years ago
Is 19 equal to 4.358
AURORKA [14]

Answer:

No

Step-by-step explanation:

19=19 and 4.358=4.358

7 0
2 years ago
Write the equation of the line graphed below in Point-Slope form. Use the point labeled on the graph. State the slope and point.
saw5 [17]

Given:

The graph of a line.

To find:

The point-slope form of the given line.

Solution:

From the given graph it is clear that the line passes through the point (1,5) and (0,-1). So, the slope of the line is:

m=\dfrac{y_2-y_1}{x_2-x_1}

m=\dfrac{-1-5}{0-1}

m=\dfrac{-6}{-1}

m=6

The slope of the line is 6 and it passes through the point (1,5). So, the point slope form of the line is:

y-y_1=m(x-x_1)

y-5=6(x-1)

Therefore, the point-slope form is y-5=6(x-1), slope is 6 and the point is (1,5).

6 0
3 years ago
In shop class, you make a table. The sides of the table measure 36" and 18". If the diagonal of the table measures 43", is the t
Lunna [17]

Answer: 75

Step-by-step explanation: took test and got it right. this is not fake like other people

5 0
3 years ago
The savings account offering which of these APRs and compounding periods offers the best APY?
zzz [600]
\bf \qquad  \qquad  \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\


\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\


\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1
7 0
3 years ago
Read 2 more answers
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