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3 years ago

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A biology experiment calls for 10 milliliters of water. How much water does the experiment call for in centiliters? (a.1 (b10 (c

.100 (d1000 plz help mehhhhhhhhhhhhh

1 answer:

Tasya [4]3 years ago

7 0

It will call for A: One Centiliter. It's the same terms for stuff like millimeters and centimeters, 1 cm = 10 mm, 1 cl = 10 ml

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Factor completely: 3x2 + 2x - 1

Alex777 [14]

$3x^{2}+2x-1=3x^{2}+3x-x-1= \\ \\ 3x(x+1)-(x+1)=(3x-1)(x+1)$

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3 years ago

Read 2 more answers

Consider the following hypothesis test.H0:μ1−μ2=0 Ha:μ1−μ2≠0The following results are for two independent samples taken from the

Julli [10]

Answer:

a) $z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

b) $p_v =2*P(z$

c) Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

Step-by-step explanation:

Information given

$\bar X_{1}= 104$ represent the mean for 1

$\bar X_{2}= 106$ represent the mean for 2

$\sigma_{1}= 8.4$ represent the population standard deviation for 1

$\sigma_{2}= 7.6$ represent the population standard deviation for 2

$n_{1}=80$ sample size for the group 1

$n_{2}=70$ sample size for the group 2

z would represent the statistic

Hypothesis to test

We want to check if the two means for this case are equal or not, the system of hypothesis would be:

H0: $\mu_{1}=\mu_{2}$

H1: $\mu_{1} \neq \mu_{2}$

The statistic would be given by:

$z =\frac{\bar X_1-\bar X_2}{\sqrt{\frac{\sigma^2_1^2}{n_1} +\frac{\sigma^2_2^2}{n_2}}}=$ (1)

Part a

Replacing we got:

$z =\frac{104-106}{\sqrt{\frac{8.4^2}{80} +\frac{7.6^2}{70}}}= -1.53$

Part b

The p value would be given by this probability:

$p_v =2*P(z$

Part c

Since the p value is higher than the significance level provided we have enogh evidence to FAIL to reject the null hypothesis and we can't conclude that the true means are different at 5% of significance

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3 years ago

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andrew-mc [135]

In the attachement, there is what I came up with so far. I think that finding 'a' is non-trivial, if possible at all.

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Ulleksa [173]

Answer:

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Step-by-step explanation:

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Answer:

a) see the plots below

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Step-by-step explanation:

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