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3 years ago

7 pints and 9 cups equals how many pints

Mathematics

2 answers:

olga2289 [7]3 years ago

8 0

Answer:

They equal 11.5 pints.

erik [133]3 years ago

5 0

Answer:

Altogether this would equal 11 1/2 pints

<em>Hope this helped!! Have a god day c;</em>

Step-by-step explanation:

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What is 150/100 in decimal form and percent form

Andrews [41]

Decimal : 1.5
Percent : 150%

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3 years ago

Find the volume and surface area of the composite figure. Give your answer in terms of pi

ExtremeBDS [4]

Given:

A diagram of a composite figure.

Radius of cone and hemisphere is 8 cm.

Height of the cone is 15 cm.

To find:

The volume and the surface area of the composite figure.

Solution:

Volume of a cone is:

$V_1=\dfrac{1}{3}\pi r^2h$

Where, r is the radius and h is the height of the cone.

Putting $r=8,h=15$ in the above formula, we get

$V_1=\dfrac{1}{3}\pi (8)^2(15)$

$V_1=\pi (64)(5)$

$V_1=320\pi$

Volume of the hemisphere is:

$V_2=\dfrac{2}{3}\pi r^3$

Where, r is the radius.

Putting $r=8$ , we get

$V_2=\dfrac{2}{3}\pi (8)^3$

$V_2=\dfrac{1024}{3}\pi$

$V_2\approx 341.3\pi$

Now, the volume of the composite figure is:

$V=V_1+V_2$

$V=320\pi +341.3\pi$

$V=661.3\pi$

The volume of the composite figure is 661.3π cm³.

The curved surface area of a cone is:

$A_1=\pi r\sqrt{h^2+r^2}$

Where, r is the radius and h is the height of the cone.

Putting $r=8,h=15$ in the above formula, we get

$A_1=\pi (8)\sqrt{(15)^2+(8)^2}$

$A_1=\pi (8)\sqrt{289}$

$A_1=\pi (8)(17)$

$A_1=136 \pi$

The curved surface area of the hemisphere is:

$A_2=2\pi r^2$

Where, r is the radius.

Putting $r=8$ , we get

$A_2=2\pi (8)^2$

$A_2=2\pi (64)$

$A_2=128\pi$

Total surface area of the composite figure is:

$A=A_1+A_2$

$A=136\pi +128\pi$

$A=264\pi$

The total surface area of the composite figure is 264π cm².

Therefore, the correct option is A.

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3 years ago

What does x=_________

cluponka [151]

Answer:

x = 130˚

Step-by-step explanation:

x + 100˚ = 360˚

2 x = 360˚ - 100˚

2 x = 260˚

260˚ ÷ 2 = 130˚

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3 years ago

ABC has vertices A(0,6) B(4,6) C(1,3). Sketch a graph of ABC and use it to find the orthocenter of ABC. Then list the steps you

kumpel [21]

<span> Plot the points and draw the triangle. Now you have to draw a line that passes through a point, perpendicular to the triangle side that it's opposite from. Then do that again with a second point. The intersection of these two points will give you the Orthocenter. (You don't need to do it for the third point; it will pass through it anyway, but you only need two intersecting lines to define a point!) Since AB is a horizontal line, it will probably be easiest to start with the line perpendicular to AB that passes through C. You'll find that this is just the vertical line x=1. Now just pick another point and do it again. (Hint: if you know two points, you can find their slope, and you know that lines perpendicular to each other have negative reciprocal slopes.)</span>

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3 years ago