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Tems11 [23]
3 years ago
11

4x+2y=10 3x+2y=6 Solve the system algebraically.

Mathematics
1 answer:
nignag [31]3 years ago
8 0

Answer:

x=4

y=-3

Step-by-step explanation:

we are given system of equations as

4x+2y=10

3x+2y=6

we can subtract both equations

and we get

4x+2y-(3x+2y)=10-6

4x+2y-3x-2y=10-6

x=4

now, we can find y

we can plug x=4 into anyone equation

4\times 4+2y=10

16+2y=10

16+2y-16=10-16

2y=-6

y=-3

so, we get solution as

x=4

y=-3


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Answer :    x=−5

Step-by-step explanation: Step 1: Simplify both sides of the equation.

−3−3x=−4(2x+7)

−3+−3x=(−4)(2x)+(−4)(7)(Distribute)

−3+−3x=−8x+−28

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Step 2: Add 8x to both sides.

−3x−3+8x=−8x−28+8x

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Step 3: Add 3 to both sides.

5x−3+3=−28+3

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Step 4: Divide both sides by 5.

5x /5 =  −25 /5

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Answer:

x=−5

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