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3 years ago

11

4x+2y=10 3x+2y=6 Solve the system algebraically.

1 answer:

nignag [31]3 years ago

8 0

Answer:

$x=4$

$y=-3$

Step-by-step explanation:

we are given system of equations as

$4x+2y=10$

$3x+2y=6$

we can subtract both equations

and we get

$4x+2y-(3x+2y)=10-6$

$4x+2y-3x-2y=10-6$

$x=4$

now, we can find y

we can plug x=4 into anyone equation

$4\times 4+2y=10$

$16+2y=10$

$16+2y-16=10-16$

$2y=-6$

$y=-3$

so, we get solution as

$x=4$

$y=-3$

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