Ask question

Ask question

All categories

3 years ago

11

Convert the expression (p/q)^2/5 to its radical form.

1 answer:

solniwko [45]3 years ago

6 0

$\left(\dfrac{p}{q}\right)^\frac{2}{5}=\sqrt[5]{\left(\dfrac{p}{q}\right)^2}=\sqrt[5]{\dfrac{p^2}{q^2}}\\\\Used:\\\\a^\frac{m}{n}=\sqrt[n]{a^m}$

You might be interested in

What is the horizontal asymptote of f (x) =StartFraction negative 2 x Over x + 1 EndFraction? y = –2 y = –1 y = 0 y = 1

miv72 [106K]

Answer:

y = -2

Step-by-step explanation:

Any asymptotes of a rational function will be described by the quotient of the numerator and denominator (excluding any remainder).

$f(x)=\dfrac{-2x}{x+1}=-2+\dfrac{2}{x+1}$

The horizontal asymptote is ...

y = -2

8 0

3 years ago

Read 2 more answers

Please help me with this problem. I'm stuck!!

mihalych1998 [28]

$\bf S(t)=4\pi \left( \cfrac{3}{8}t^4 \right)^2\impliedby \textit{distributing the exponent}
\\\\\\
S(t)=4\pi \left( \cfrac{3^2}{8^2}t^{4\cdot 2} \right)\implies S(t)=4\pi \cdot \cfrac{9t^8}{64}\implies S(t)=\cfrac{4}{64}\cdot \cfrac{9\pi t^8}{1}
\\\\\\
S(t)=\cfrac{1}{16}\cdot \cfrac{9\pi t^8}{1}\implies S(t)=\cfrac{9\pi t^8}{16}$

6 0

3 years ago

Rewrite as difference of squares (2x+5)(2x-5)

andre [41]

4x^2-25

I got u homie wherever in the world u r

4 0

3 years ago

You are going running. For every mile you run, you burn 100 calories. In the graph and table below, m represents the number of m

Volgvan

I think you need to pit in a graph or draw one yourself, eat mile lable that you ran 100 miles and keep going

5 0

3 years ago

Kenyon ran for 8 miles each week while training. Here is his record of the number of miles he ran.

diamong [38]

Step-by-step explanation:

Let x be the miles Kenyon ran on tuesday

Let y be the miles Kenyon ran on thursday

Given,

Mon + Tues + Wed + Thu = 8mi

$1.2 + x + 1.6 + y = 8 \\ 2.8 + x + y = 8 \\ x + y = 8 - 2.8 \\ x + y = 5.2$

also given,

$y = x + 0.4 \\ - x + y = 0.4$

Now we have x + y = 5.2 as equation 1 and -x + y = 0.4 as equation 2

Using equation 1,

$x + y = 5.2 \\ x = 5.2 - y$

Substitute this equation into equation 2.

$- (5.2 - y) + y = 0.4 \\ - 5.2 + y + y = 0.4 \\ - 5.2 + 2y = 0.4 \\ 2y = 0.4 + 5.2 \\ 2y = 5.6 \\ y = 5.6 \div 2 \\ = 2.8mi$

Substitute y = 2.8 into equation 1.

$x + 2.8 = 5.2 \\ x = 5.2 - 2.8 \\ = 2.4mi$

Therefore Kenyon ran 2.4 miles on tuesday, and ran 2.8 miles on thursday.

8 0

2 years ago