I think it's D as an answer but I could be wrong
Both a rhombus and a rectangle have diagonals that are perpendicular bisectors, but the ones formed in a square are all congruent, so that is probably the most descriptive one.
Answer:
46
Step-by-step explanation:
The geometry can be modeled by a right triangle. The diagonal measure is the hypotenuse, and the height is one leg. The width is the other leg, and can be found using the Pythagorean theorem.
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<h3>Pythagorean theorem</h3>
The relation between the leg lengths (a, b) and the hypotenuse (c) is ...
c² = a² +b²
Solving for b gives ...
b = √(c² -a²)
<h3>application</h3>
In this problem, we have c=55 and a=30. Then the width of the TV is ...
b = √(55² -30²) = √(3025 -900) = √2125
b ≈ 46.098
The width of the TV is about 46.
Answer:
12.42 units
Step by step explanation:
Given,
length of the radius = 2 units
Therefore, arc length of the complete circle = 2 × 3.14 × 2 units = 12.56 units
Therefore, arc length of the partial circle = 3/4 × 12.56 units
= 12.42 units
<span>a whole number; a number that is not a fraction.</span>