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stich3 [128]
3 years ago
11

Plss do this too question

Mathematics
1 answer:
Ivahew [28]3 years ago
3 0
13. B
14. B
Hope this helps!!
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BRAINLIEST AND 21 POINTS NEED HELP ASAP
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I'm notttt sureeeeee I think its C i don't know,

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3 years ago
Determine the point of intersection between the lines with equations x+3y=5 and 3x−2y=26.
Zolol [24]

Answer:

the ans is :

Step-by-step explanation:

First, it would be helpful to draw a quick sketch of the lines. It helps to visualize the problem.

To find the intersection point, we need to find the point where x and y are the same value in both equations.

The line equations:

6x+2y=26 ................... 1

2x+3y=18 ................... 2

Can be rearranged to the common line equation form: y = mx + c

y = 13 - 3x ................... 3

y = 6 - 2/3 x ................. 4

At the intersection point, y will be equal for both equations. So, we can set 3 equal to 4 and solve for x.

13- 3x = 6 - 2/3 x

13 = 6 + 3x - 2/3x ....... add 3x to both sides

13 = 6 + 2 1/3x ........ simplify

7 = 2 1/3 x ........ subtract 13 from both sides

7 = 7/3 x ......... multiply both sides by 3/7

3 = x

To calculate the y-coordinate substitute x = 3 into 3.

y = 13 - 3x

y = 13 - 3(3)

y = 4

To check your answer, substitute the values for x and y into the other equation, 4.

The point of intersection is (3,4).

If you drew a sketch of the problem, you should be able to see that this point of intersection makes sense.

4 0
3 years ago
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What is the product of a 1 digit nunber and a 4 digit number
Inessa05 [86]
It depends on the number but you can say 345 times 2 and the answer is 690. Hope that helps.
7 0
3 years ago
27.3% of as fraction
Kruka [31]

Answer:

273/1000

Step-by-step explanation:

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3 years ago
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A complex number z_1z 1 ​ z, start subscript, 1, end subscript has a magnitude |z_1|=6∣z 1 ​ ∣=6vertical bar, z, start subscript
aliina [53]

Answer:

The answer is "\bold{9.19- 9.19\ i}"

Step-by-step explanation:

When the value of z_1 has the following properties:

\to |z_1| =13

\theta = 315^{\circ} \\\\ = 1.75 \pi\ \ \ \ \ \ \ \ \ \ \ \ \ \  \ _{where} \ \ (\pi = 180^{\circ})

Calculating the value of z_1 :

= 13 \times [ \cos(1.75 \pi ) + i \sin(1.75 \pi) ] \\\\=  13 \times[\cos(1.75 \pi - 2\pi ) + \ i \sin(1.75 \pi - 2\pi )]\\ \\= 13 \times [\cos(-0.25 \pi ) +\  i \sin(-0.25 \pi) ]\\\\= 13 \times [0.707106781 - 0.707106781]\\\\ =9.19 - 9.19\ i \\\\

3 0
3 years ago
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