Based on the lengths, the cheerleaders' banner is scaled down by a factor of 4.
So, 44 ÷ 4 = 11.
For the perimeter, 156 ÷ 4 is 39.
For the area, you have to do A=bh
(Area = base × height)
The base (length) is 11 inches, multiply that by two to get 22 inches which is the amount for both lengths. If the total perimeter is 39, you have to subtract 22 from that to get the remaining inches which is 17.
17÷2= 8.5 inches. The height is 8.5.
Now you can plug them in
A=bh
A=(11)(8.5)
A=93.5 in^2
The final answer is:
Area = 93.5 in^2
Length = 11 in
Perimeter = 39 in
I hope that helps!
According to Sturge's rule, number of classes or bins recommended to construct a frequency distribution is k ≈ 7
Sturge's Rule: There are no hard and fast guidelines for the size of a class interval or bin when building a frequency distribution table. However, Sturge's rule offers advice on how many intervals one can make if one is genuinely unable to choose a class width. Sturge's rule advises that the class interval number be for a set of n observations.
Given,
n = 66
We know that,
According to Sturge's rule, the optimal number of class intervals can be determined by using the equation:

Here, n is equal to 66 and by substituting the value to the equation we get:

k = 7.0444
k ≈ 7
Learn more about Sturge's rule here: brainly.com/question/28184369
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Answer:
A Euler circuit has two ODD verticles.
I hope that this helps.
Step-by-step explanation:
Answer:
False.
Step-by-step explanation:
Apex
The correct answer would be C. Hope that helps.