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ValentinkaMS [17]
3 years ago
7

A rectangle school banner has a length of 44 inches, a perimeter of 156 inches , and an area of 1496 square inches. The cheerlea

ders make signs similar to the banner. The length of a sign is 11 inches. What is its perimeter and its area ?
Mathematics
1 answer:
Andrej [43]3 years ago
7 0
Based on the lengths, the cheerleaders' banner is scaled down by a factor of 4.

So, 44 ÷ 4 = 11.

For the perimeter, 156 ÷ 4 is 39.

For the area, you have to do A=bh
(Area = base × height)

The base (length) is 11 inches, multiply that by two to get 22 inches which is the amount for both lengths. If the total perimeter is 39, you have to subtract 22 from that to get the remaining inches which is 17.
17÷2= 8.5 inches. The height is 8.5.

Now you can plug them in
A=bh
A=(11)(8.5)
A=93.5 in^2

The final answer is:
Area = 93.5 in^2
Length = 11 in
Perimeter = 39 in

I hope that helps!
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iren2701 [21]

Answer:

w = 33.94 ft

Step-by-step explanation:the roof takes the shape of a right angle. The top of the roof is a right angle. To find the width of the house, which is the hypotenuse of the triangular roof, we would apply pythagorean theorem.

Thus:

w^2 = 24^2 + 24^2

w^2 = 1,152

Square both sides

\sqrt{w^2} = \sqrt{1,152}

w = 33.94 (to 2 decimal places)

The width of the house = 33.94 ft

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3 years ago
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(x - 4)² + (y - 8)² = 6.25
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Hello,

cos 160°=-q

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tan -20°=tan 160=√(1-q²)/-q

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Answer:

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