Answer:
Well, it keeps going down in 15s, so I'm guessing it's a geometric sequence. I wouldn't know about common ratio though...
Answer:
(f-g)(x)=-x^(2)+2x+8
the solutions are:
<em><u>x=4 or x=-2</u></em>
Step-by-step explanation:
(f-g)(x)=2x+1-(x^(2)-7)
(f-g)(x)=-x^(2)+2x+1+7
(f-g)(x)=-x^(2)+2x+8
does this help or should I solve for the zeros/solutions of this quadratic equation?
then:
-x^(2)+2x+8=0
-(x^(2)-2x-8)=0
x^(2)-2x-8=0
(x-4)(x+2)=0
<em><u>x=4 or x=-2</u></em>
Answer:
x = 2 or x = 4
Step-by-step explanation:
Solve: 2 log x = log 2 + log(3x - 4)
log (x^2) = log 2 + log (3x - 4)
log (x^2) = log [2*(3x - 4)]
x^2 = 2*(3x - 4)
x^2 = 6x - 8
x^2 - 6x + 8 = 0
factor:
(x - 2 )(x - 4) = 0
x = 2 or x = 4
4x+ 4(10)=64
4x+ 40 =64
4x=24
x=6
If you need I can explain the steps more but I hope this helps!
