Answer:
C. solution:
3(3c-2) = 5(2c-1)
or, 9c-6 = 10c-5
or, -6+5 =<em> </em>10c-9c
or, -1 = 1c
Hence, c = -1.
D. solution:
5(5-2a) = 4(6-a)
or, 25-10a = 24 - 4a
or, 25-24 = -4a+10a
or, 1 = 6a
or, 1/6 = a
Hence, a = 1/6.
The main property is as follow
(A^p)^q=A^pxq
so only Sam's work is correct because
(8^4)^5 x(7^3)^9=(8^4x5)x(7^3x9)=8^20x 7^27
Answer:
Its C but the way I got is too small so I cant really give explanation
Answer:
In Expanded notation it is 
In numerals it is 6.05
Step-by-step explanation:
Expanded notation
Expanded notation is a helpful way to rewrite numbers in order to show the place value of each digit.
Normal number of we have
.........,Hundred, Tens ,Unit
eg. 1.) 514
5 = hundred place
1 = tens place
4= unit place
Now for decimal numbers
tenths,hundredths,thousandths........
eg. 1.) 0.25
0 = unit place
2 = tenths place 
5 = hundredths place 
We will have example in numerals and it expanded notation.
1.
6.05 ( six and five hundredths)
Expanded form

Here,
6 is in Unit place
0 is in Tenths place
5 is in Hundredths place