1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ANEK [815]
3 years ago
6

Which change will double the lateral surface area of a regular triangular pyramid with base length b, height h, and slant height

l? double each side, b, of the base triangle while keeping the slant height, l, the same. double the height, h, of the pyramid while keeping each base length, b, the same?
Mathematics
1 answer:
kotegsom [21]3 years ago
8 0
The choice that will affect the surface area of the lateral face has to do with doubling ONLY one of the dimensions of the lateral face.

The second choice explains that the height is doubled while the length of the base remains unchanged. This is the correct answer.
You might be interested in
Please help me with this
juin [17]

Answer:

x=30, <A=60, <C=30

Step-by-step explanation:

A triangle always has its total angles added up to 180 degrees, so we can set up the following equation:

90+2x+x=180

90+3x=180

3x=90

x=30

Since x=30, this means <C is 30 degrees. For <A, it's twice as much as <C, so 2*30=60.

So x=30, <A=60, <C=30

Hope this helped!

8 0
3 years ago
Read 2 more answers
Two complementary angles are congruent. Which equation gives the measure in degrees, d, of each angle?
Lelechka [254]
2d=90
d=45
complementary angles add up to 90 degrees. If the two angles are congruent, it means that both angles have the same measurements
6 0
3 years ago
A company produces steel rods. The lengths of the steel rods are normally distributed with a mean of 236.8-cm and a standard dev
RSB [31]

Transform M to the standard normally distributed random variable Z via

Z=\dfrac{M-\mu_M}{\sigma_M}

where \mu_M and \sigma_M are the mean and standard deviation for M, respectively. Then

P(236.5

5 0
4 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
3 years ago
Solve for z.<br><br> –2.9 + 4.2z = –14.73 − 12.74 + 0.3z<br><br> z =
Kobotan [32]

Answer:

\boxed{z = -6.3}

Step-by-step explanation:

=  >  - 2.9 + 4.2z =  - 14.73 - 12.74 + 0.3z \\  \\  =  >  - 2.9 + 4.2z =  - 27.47 + 0.3z \\  \\  =  > 4.2z - 2.9 =  0.3z - 27.47 \\  \\  =  > 4.2z - 0.3z - 2.9 =  - 27.47 \\  \\  =  > 3.9z =  - 27.47 + 2.9 \\  \\  =  > 3.9z =  - 24.57 \\  \\  =  > z =  -  \frac{24.57}{3.9}  \\  \\  =  > z =  - 6.3

4 0
3 years ago
Other questions:
  • Do you think it is true that any solution point of the equation y=1/2x+1 is a point on the line?
    11·1 answer
  • Write the expression add thirty-eight and fifty-two, then divide by four and half.
    13·1 answer
  • Helppp
    5·1 answer
  • This graph represents a linear function.
    8·1 answer
  • 200 trials of picking colored blocks, dean picked 63 yellow blocks. Jeanne did the same process and after 100 trials she picked
    6·2 answers
  • Simplify the expression 6 + (12 + x).<br> 6+ (12 + x) = 0<br> I really need helppp
    8·1 answer
  • By law, sales tax has to be applied to the discount price. However, would it be better for the consumer if the 7.5% sales tax wa
    9·2 answers
  • Find the least whole number N so that 2020 + N is exactly divisible by 11.
    7·1 answer
  • The equation of a circle centered at the orgin is x^2 + y^2 = 16. What is the radius of the circle
    7·1 answer
  • How to add fractions with whole numbers.
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!