Answer:
![p = 32\: \: in](https://tex.z-dn.net/?f=p%20%3D%2032%5C%3A%20%20%5C%3A%20in)
![a = 49 {in}^{2}](https://tex.z-dn.net/?f=a%20%3D%2049%20%7Bin%7D%5E%7B2%7D%20)
Step-by-step explanation:
![perimeter \\ = 8 + 8+8+8 \\ = 32 \: \: in](https://tex.z-dn.net/?f=perimeter%20%5C%5C%20%20%3D%208%20%2B%208%2B8%2B8%20%5C%5C%20%20%3D%2032%20%5C%3A%20%20%5C%3A%20in)
![area \\ 1)3 \times 8 = 24 \\ 2)5 \times 5 = 25 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 49 {in}^{2}](https://tex.z-dn.net/?f=area%20%5C%5C%20%20%201%293%20%5Ctimes%208%20%3D%2024%20%5C%5C%202%295%20%5Ctimes%205%20%3D%2025%20%5C%5C%20%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%20%5C%3A%20%3D%2049%20%7Bin%7D%5E%7B2%7D%20)
hope this helps
brainliest appreciated
good luck! have a nice day!
Answer: I Think it is b
Step-by-step explanation:
The area of the paper is the amount of space it occupies.
The length of papers around the edge is 1607680 cm
The given parameters are:
![\mathbf{d_1 = 60cm}](https://tex.z-dn.net/?f=%5Cmathbf%7Bd_1%20%3D%2060cm%7D)
![\mathbf{d_2 = 60cm + 8cm = 68cm}](https://tex.z-dn.net/?f=%5Cmathbf%7Bd_2%20%3D%2060cm%20%2B%208cm%20%3D%2068cm%7D)
The area of the circle head is:
![\mathbf{Area = \pi \frac{d^2}{4}}](https://tex.z-dn.net/?f=%5Cmathbf%7BArea%20%3D%20%5Cpi%20%5Cfrac%7Bd%5E2%7D%7B4%7D%7D)
So, we have:
![\mathbf{Area = \pi \frac{d_2^2 - d_1^2}{4}}](https://tex.z-dn.net/?f=%5Cmathbf%7BArea%20%3D%20%5Cpi%20%5Cfrac%7Bd_2%5E2%20-%20d_1%5E2%7D%7B4%7D%7D)
Substitute known values
![\mathbf{Area = \pi \frac{68^2 - 60^2}{4}}](https://tex.z-dn.net/?f=%5Cmathbf%7BArea%20%3D%20%5Cpi%20%5Cfrac%7B68%5E2%20-%2060%5E2%7D%7B4%7D%7D)
![\mathbf{Area = \pi \frac{1024}{4}}](https://tex.z-dn.net/?f=%5Cmathbf%7BArea%20%3D%20%5Cpi%20%5Cfrac%7B1024%7D%7B4%7D%7D)
![\mathbf{Area = 256\pi}](https://tex.z-dn.net/?f=%5Cmathbf%7BArea%20%3D%20256%5Cpi%7D)
The length of the paper is then calculated as:
![\mathbf{Length = \frac{Area}{0.0005}}](https://tex.z-dn.net/?f=%5Cmathbf%7BLength%20%3D%20%5Cfrac%7BArea%7D%7B0.0005%7D%7D)
This gives
![\mathbf{Length = \frac{256\pi}{0.0005}}](https://tex.z-dn.net/?f=%5Cmathbf%7BLength%20%3D%20%5Cfrac%7B256%5Cpi%7D%7B0.0005%7D%7D)
![\mathbf{Length = \frac{256 \times 3.14}{0.0005}}](https://tex.z-dn.net/?f=%5Cmathbf%7BLength%20%3D%20%5Cfrac%7B256%20%5Ctimes%203.14%7D%7B0.0005%7D%7D)
![\mathbf{Length = 1607680}](https://tex.z-dn.net/?f=%5Cmathbf%7BLength%20%3D%201607680%7D)
Hence, the length of papers around the edge is 1607680 cm
Read more about areas at:
brainly.com/question/2264643
Answer:
TRUE
Step-by-step explanation:
GIVE ME BRAINLIEST