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olya-2409 [2.1K]
1 year ago
10

Simplify 1/3a+3/5-1/15+2/3a

Mathematics
2 answers:
Misha Larkins [42]1 year ago
7 0

Answer:\frac{15+8a}{15a}

Step-by-step explanation:

=\frac{1}{3a} +\frac{3}{5} -\frac{1}{15}+ \frac{2}{3a} \\= \frac{1}{3a} +\frac{8}{15} +\frac{2}{3a} \\=\frac{5+8a+10}{15a} \\=\frac{15+8a}{15a}

erica [24]1 year ago
3 0

Answer:

15+8a

-------------

15a. the calculating and collecting like terms

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One​ year, the mean age of an inmate on death row was 39.2 years. A sociologist wondered whether the mean age of a​ death-row in
Volgvan

Answer:

The 95% confidence interval about the mean age is between 17.6 years and 57.6 years.

This means that we are 95% sure that the mean age of an inmate in the death row is in this interval. 39.2 is part of this interval, which implies that the mean age of a​ death-row inmate has not changed since then.

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We have the sample standard deviation, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 32 - 1 = 31

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 31 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.95}{2} = 0.975. So we have T = 2.0395

The margin of error is:

M = T*s = 2.0395*9.8 = 20

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The lower end of the interval is the sample mean subtracted by M. So it is 37.6 - 20 = 17.6 years

The upper end of the interval is the sample mean added to M. So it is 37.6 + 20 = 57.6 years.

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This means that we are 95% sure that the mean age of an inmate in the death row is in this interval. 39.2 is part of this interval, which implies that the mean age of a​ death-row inmate has not changed since then.

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