All categories

3 years ago

60 cars to 24 cars what is the percent of change can you tell me answer and explain thanks

1 answer:

3 0

Assuming you meant there were 60 cars and then 36 went off somewhere and you are left with 24 cars, the percent of change is 250% because 60/24=2.5, multiply that by 100 (to get percent) will get you 250%.

You might be interested in

I need help. Work has to be shown but i don’t know how to do them

mote1985 [20]

Step-by-step explanation:

1% of 500 is 5 so multiply 5 by 8 for one year. which is 40 so multiply that by 2.

1% of 500 = 5

5 × 8 = 40

40 × 2 = 80

1% of 1000 = 10

10 × 5 = 50

50 × 3 = 150

12 months = 6%

6/12 = 1 month

0.5 = 1 month

0.5 × 9 = 4.5 (the amount of interest for 9 months.)

800 × 4.5% = 36

12 months = 7%

7/12 = 1 month ( i'll leave this in fraction form because of the decimal points.)

7/12 x 8 = 4.666667 or 4.7 rounded.

1200 × 4.7% = 56.40

8 0

2 years ago

Is sam had 15 candies and gave three to Emma 5 to jack how many does he have left

spin [16.1K]

Hello!

If he has 15 and gives away 3 he has 12. If he gives away 5 more he will have 7.

I hope this helps!

3 0

3 years ago

Can someone help me with this ????

fenix001 [56]

Answer:

$(\frac{3}{3+5})(2 - (-14))+ (-14)$

Step-by-step explanation:

Given

Ratio = 3:5

Q = -14

S = 2

Required

Which solution uses $(\frac{m}{m+n})(x_2 - x_1)+ x_1$

From the given parameters;

$m:n = 2:5$

$m = 2\ and\ n = 5$

$x_1 = -14\ and\ x_2 = 2$

Substitute the above values in $(\frac{m}{m+n})(x_2 - x_1)+ x_1$

This gives:

$(\frac{m}{m+n})(x_2 - x_1)+ x_1$

$(\frac{3}{3+5})(2 - (-14))+ (-14)$

From the list of given options, only option A uses the given form of the formula...

6 0

3 years ago

Find the directional derivative of the function at the given point in the direction of the vector v. G(r, s) = tan−1(rs), (1, 3)

alexandr1967 [171]

The directional derivative of $f$ at the given point in the direction indicated is $\frac{5}{2}$ .

<h3>How to calculate the directional derivative of a multivariate function</h3>

The directional derivative is represented by the following formula:

$\nabla_{\vec v} f = \nabla f (r_{o}, s_{o})\cdot \vec v$ (1)

Where:

$\nabla f (r_{o}, s_{o})$ - Gradient evaluated at the point $(r_{o}, s_{o})$ .
$\vec v$ - Directional vector.

The gradient of $f$ is calculated below:

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{\partial f}{\partial r}(r_{o},s_{o}) \\\frac{\partial f}{\partial s}(r_{o},s_{o}) \end{array}\right]$ (2)

Where $\frac{\partial f}{\partial r}$ and $\frac{\partial f}{\partial s}$ are the partial derivatives with respect to $r$ and $s$ , respectively.

If we know that $(r_{o}, s_{o}) = (1, 3)$ , then the gradient is:

$\nabla f(r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{s}{1+r^{2}\cdot s^{2}} \\\frac{r}{1+r^{2}\cdot s^{2}}\end{array}\right]$

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{1+1^{2}\cdot 3^{2}} \\\frac{1}{1+1^{2}\cdot 3^{2}} \end{array}\right]$

$\nabla f (r_{o}, s_{o}) = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right]$

If we know that $\vec v = 5\,\hat{i} + 10\,\hat{j}$ , then the directional derivative is:

$\nabla_{\vec v} f = \left[\begin{array}{cc}\frac{3}{10} \\\frac{1}{10} \end{array}\right] \cdot \left[\begin{array}{cc}5\\10\end{array}\right]$

$\nabla _{\vec v} f (r_{o}, s_{o}) = \frac{5}{2}$

The directional derivative of $f$ at the given point in the direction indicated is $\frac{5}{2}$ . $\blacksquare$

To learn more on directional derivative, we kindly invite to check this verified question: brainly.com/question/9964491

3 0

2 years ago

What is the length of AC

Arte-miy333 [17]

Answer:

126

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers