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Crazy boy [7]
3 years ago
15

The vertices of / are G(–4, 0), H(5, 2), and I(–2, –3). / is rotated 270° counterclockwise about the origin to form /. What are

the coordinates of the vertices of /?
Mathematics
1 answer:
Airida [17]3 years ago
6 0

vertices of I are(-2,-3)

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Simplify the following algebraic expression:<br> 4+3 [6z - 5(6 +2z)]
Tatiana [17]

\huge\text{Hey there!}

\huge\text{4+3 [6z - 5(6 +2z)]}

\huge\text{4+(3)(6z)+(3)(-5(6+2z))}\\\\\rightarrow\huge\text{4+18z+(-30z)+(-90)}

\huge\text{\bf{Combine the like terms if you have any.}}

\huge\text{Like term \#1: 10z \& -30z}\\\\\\\huge\text{Like term \#2: 4 \& -90}

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\boxed{\boxed{\huge\text{Answer: -12z + (-86)}}}\huge\checkmark

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5 0
3 years ago
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I have 7 mins to turn in, what’s the answer?? thanks :)
Ostrovityanka [42]

Answer:

A) x = 10-/3, y = 20

Step-by-step explanation:

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Kazeer [188]

Answer:

C. quadratic function; quadratic term: −6x^2; linear term: −17x; constant term: −12

Step-by-step explanation:

Answer:

quadratic function; quadratic term: −6x² ; linear term: −17x; constant term: −12

Step-by-step explanation:

The given function is

We need to expand the RHS to get:

We can see that the degree of this polynomial function is 2 and hence it is a quadratic function.

The quadratic term is -6x²

The linear term is -17x

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y=-1-2*2=-1-4=-5
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3 years ago
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