Let it be x
42x=28
x=0.66666666
x=66.67%
If (x-2) is a factor of P(x), then what do you think P(x) will be if x = 2? If x is 2 then won't x-2 be zero? And if a factor of of P(x) is zero, won't P(x) be zero, too (regardless of what the other factor is)?
So the "proper value" to test is x=2. If P(2) = 0 then x-2 must be a factor and if P(2) is not zero then x-2 is not a factor is
.3x-x+2=4
I'll leave it up to you so simplify this and find out if x-2 is a factor.
P.S. As I indicated above you use P(2) to see if (x-2) is a factor. P(-2) checks to see if (x-(-2)) or (x+2) is a factor. P(-2) does not check for a factor of (x-2)! Please redo the problem and see what P(2) works out to be!
<h3>
Answer: 5</h3>
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Explanation:
Apply the difference of squares rule
x^2 - y^2 = (x-y)(x+y)
x^2 - y^2 = (5)(1)
x^2 - y^2 = 5
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Alternatively, you can solve the system
for x and y to get (x,y) = (3,-2).
Then compute x^2-y^2 = 3^2-(-2)^2 = 9-4 = 5
Both x and y are positive
The answer is x=2
Remember, first add/substract the like terms, in this case 6x-10x to get -4x. Then, add 8x to negative 8x to cancel it out and do the same thing to -4x. Do this with all your terms and you should get 4x=8. Then divide both sides by 4 to get x=2.