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klio [65]
3 years ago
12

Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = π/ 2 ?

Mathematics
1 answer:
Aneli [31]3 years ago
3 0
That answer was (B)................
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The order pairs (1, 2), (2, 5), (3, 10), (4, 17), and (5, 26) represent a function. what is a rule that could represent this fun
LenaWriter [7]
The X which is the first number in each () in called the input
There is only one input for every number
Meaning all the first numbers mystery br DIFFERENT
6 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
3 years ago
Ashley deposits $500 into an account that earns 2% interest compounded 3 times per year. How much money will Ashley have in her
Vadim26 [7]
A=p (1+r/k)^kt
A=500×(1+0.02÷3)^(3×4)
A=541.50
5 0
3 years ago
a contractor is building a new subdivision on the outside of a city. he has started work on the first street and is planning for
monitta

The equation of the location of the second street in standard form is

x + y = -6

Equation of the line:

The equation of the line represents the algebraic form of representing the set of points, which together form a line in a coordinate system.

The equation of the line can be formed with the help of the slope of the line and a point on the line.

The general form of the equation of a line with a slope m and passing through the point (x₁,y₁) is given as:

y = mx + b.

Where

m represents the slope of the line.

Given,

Point = ( -5 , -1)

Here we need to find the equation of the location.

For that, first we have to find the slope of the line,

Having two points in the format (x,y), the slope is given by the change in y divided by the change in x.

The equation of the street is parallel to the equation of the line in the graph, thus they have the same slope.

So, in street 1 the equation is

=> y =-x +1

And street 2 the equation is  

=> y =-x +b,  

solve for b by plugging in (-5,-1)

=> -1 =-(-5) +b

=> b= -1-5 = -6

=> b = -6

Now apply the value of b on the equation,

Then

=> y = -x -6

=> y + x = -6

So, the equation of the location is x + y = -6.

To know more about Equation of the line here.

brainly.com/question/2564656

#SPJ4

7 0
1 year ago
Determine the perimeter
nordsb [41]

Answer:

139

Step-by-step explanation:

14+14+28+33+33+17 = 139

6 0
3 years ago
Read 2 more answers
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