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klio [65]
3 years ago
12

Where are the asymptotes of f(x) = tan(4x − π) from x = 0 to x = π/ 2 ?

Mathematics
1 answer:
Aneli [31]3 years ago
3 0
That answer was (B)................
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R. The First letter comes before S, T, U, V, and W
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The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc
AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

p \propto \dfrac{1}{d}

Introducing the constant of proportionality

p = \dfrac{k}{d}

If 150 pounds is required for a distance of 10 inches from the object

  • p=150 pounds
  • d=10 inches

150 = \dfrac{k}{10}\\\\k=1500

Therefore, the relationship between p and d is:

p = \dfrac{1500}{d}

When d=3 Inches

p = \dfrac{1500}{3}\\\implies p=500$ pounds

The pressure applied when the distance is 3 inches is 500 pounds.

4 0
3 years ago
Can someone help with this
mixas84 [53]

Step-by-step explanation:

-10-2x = 3x+15

5x = -25

x= -5

5 0
2 years ago
Pls check the attachment :) <br><br>f(x)=x^5-9x^3<br><br>​
Galina-37 [17]

Answer:

As x —> negative infinity, f(x) —> negative infinity

As x —> positive infinity, f(x) —> positive infinity.

Step-by-step explanation:

y =  {x}^{5}  - 9 {x}^{3}

An odd-degree function, meaning that the graph starts from negative infinity at x —> negative infinity and positive infinity at x —> positive infinity.

As x —> negative infinity, f(x) —> negative infinity

As x —> positive infinity, f(x) —> positive infinity.

An odd-degree function is an one-to-one function so whenever x approaches positive, f(x) will also approach positive.

5 0
3 years ago
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