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Kamila [148]
3 years ago
11

Which equation shows how the properties of numbers extend to negative whole numbers by the Distributive Property?

Mathematics
1 answer:
Cerrena [4.2K]3 years ago
5 0

D is the answer, i hope this helps

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A recipe that serves 6 people calls for 1 1/2 ( mixed number) pounds of meat. You have 8 pounds of meat. How many people can you
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72 people. Multiply 8 times one and a half, and then by six. 
5 0
3 years ago
How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
The following back to back stemplot represents the amount a sample of students spent on their last haircut. Because there are si
krek1111 [17]

The 5 - number summary of the distribution obtained from the boxplot is :

  • Minimum = 20
  • Maximum = 85
  • Lower quartile = 35
  • Median = 44
  • Upper quartile = 58
  • Outlier = 100

Firstly, we need to extract the values for the amount spent by females :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The five number summary include ;

  • Minimum, lower Quartile, Median, Upper Quartile and Maximum values.

Rearranging the data in ascending order :

20, 25, 25, 35, 37, 38, 39, 43, 45, 46, 50, 53, 60, 70, 85, 100

The boxplot clearly and easily gives the five number summary of the distribution :

  • Minimum = 20 (starting point of the whisker)
  • Lower quartile = 35 (starting point of the box)
  • Median = 44 (vertical line in between the box)
  • Upper quartile = 58 (endpoint of the box)
  • Maximum = 85 (endpoint of the upper whisker).

Outlier :

  • Lower boundary = LOWER QUARTILE - (1.5 × IQR)
  • Upper boundary = UPPER QUARTILE + (1.5 × IQR)
  • IQR = UPPER QUARTILE - LOWER QUARTILE
  • IQR = (58 - 35) = 23

Lower boundary = 35 - (1.5 × 23) = 0.5

Upper boundary = 58 + (1.5 × 23) = 92.5

  • The point denoted by a dot on the boxplot is an outlier = 100

Hence, values lesser than 0.5 or greater than 92.5 are outliers.

Therefore, 100 is an outlier.

Learn more : brainly.com/question/24582786

7 0
2 years ago
5a - 2b -3 + 2b - 6a simplify the expression and then write an equivalent expression. Please anyone help me it's my first questi
svet-max [94.6K]

Step-by-step explanation:

simplify the expression into like terms

so 5a-2b-3+2b-6a (add all a and b together)

this will make

-a-3

I know how to do the equivalent sorry :(

3 0
2 years ago
Read 2 more answers
10kg 20kg 24kg ?kg plz answer this for me
luda_lava [24]

Answer:

27KG

Step-by-step explanation:

Mouse- M , Cat - C, Dog - D

M + C = 10 ----- (1)

M + D = 20 -------(2)

C + D = 24 --------(3)

(1) - (2) => C - D = -10 ---- (4)

(3) + (4) => 2C = 14

                => C = 7

Substitute C in (1)  => M + 7 = 10

                            => M = 3

Substitute M in (2) => 3 + D = 20

                            => D = 17

Therefore C + M + D = 7 + 3 + 17 = 27KG

3 0
2 years ago
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