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Ksenya-84 [330]
3 years ago
5

Whats 5678 divided by 45.7​

Mathematics
2 answers:
statuscvo [17]3 years ago
8 0
The answer is 124.245076586
ddd [48]3 years ago
3 0

5678 divided by 45.7 is 124.245...

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Simplified form please help thank you
Agata [3.3K]

\dfrac{5^2}{2^{-2}}=5^2\cdot2^2=(5\cdot2)^2=10^2=100

7 0
3 years ago
GEOMETRY
Katarina [22]
SA = 2(LW + WH + LH)
SA = 2[8(6) + 6(5) + 8(5)]
SA = 2(48 + 30 + 40)
SA = 2(118)
SA = 236 square yards
5 0
2 years ago
My brother needs help
kkurt [141]

Answer:

1.95

Step-by-step explanation:

i used scientific its a caculator

3 0
2 years ago
Read 2 more answers
It is known that diskettes produced by a cer- tain company will be defective with probability .01, independently of each other.
zheka24 [161]

Answer:

1.27%

Step-by-step explanation:

To solve this problem, we may consider a binomial distribution where a customer can either accept or reject (and return) the diskette package.

Lets consider  some aspects:

1. From the formulation of the exercise we know that a package is accepted if it has at most 1 defective diskette. So our event A is defined as:

A = 0 or 1 defective diskette

2. The probability of a diskette being defective is 0.01

3. Each package contains 10 diskettes.

If X is defined as number of defective diskettes in the package, the probability of X is given by a binomial distribution with probability 0.01 and n=10

X ~ Bin(p=0.01, n=10)

Let us remember the calculation of probability for the binomial distribution:

P(X=x)=nCx*p^{x}*(1-p)^{(n-x)} with x = 0, 1, 2, 3,…, n

Where

n: number of independent trials

p: success probability  

x: number of successes in n trials

In our case success means finding a defective diskette, therefore

n=10

p=0.01

And for x we just need 0 or 1 defective diskette to reject the package

Hence,

P(X=x)=10Cx*0.01^{x}*(1-0.01)^{(10-x)} with x = 0, 1

So,

P(A)=P(X=0)+P(X=1)

P(A)=10C0*0.01^{0}*(1-0.01)^{(10-0)} + 10C1*0.01^{1}*(1-0.01)^{(9)}

P(A)=0.99^{10}+10*0.01*0.99^{9}

P(A)=0.9957

Now, because we have 3 packages and we might reject just 1 of them, we can find this probability like this:

3*(1-P(A))*P(A)*P(A) = (1-0.9957)*0.9957*0.9957=0.0127

Finally, we have that the probability of returning exactly one of the three packages is 1.27%

3 0
2 years ago
Hey anyone online who talk with me​
Lady bird [3.3K]

Answer:

here

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
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