Answer:
-2 and 4
Step-by-step explanation:
Let's set the larger number to x, and the smaller to y. With these, we can set up our equations.
x = 2y + 8
x + y = 3x - 10
Now, we put the value of x into the second equation.
2y + 8 + y = 3(2y + 8) - 10
Now we can solve for y
3y + 8 = 6y + 24 - 10
3y + 8 = 6y + 14
8 = 3y + 14
-6 = 3y
-2 = y
Now that we have the smaller number, we can put it into the first equation and solve for the larger.
x = 2*-2 + 8
x = -4 + 8
x = 4
So your two numbers are -2 and 4.
Given:
Two similar rectangles.
To find:
The area of the larger rectangle.
Solution:
Let x be the other side of the larger rectangle.
Corresponding sides of similar figures are always congruent.


The other side of larger rectangle is 2 cm.
We know that, area of rectangle is

So, area of the larger rectangle is


Therefore, the area of the larger rectangle is 8 sq. cm.
ANSWER
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Ratio of 8th graders to 7th graders = 3 : 2
Let the number of graders be 3x and 2x
Number of 8th graders = 18
So , 3x = 18
x = 18/3 = 6
Number of 7th graders = 2 × 6 = 12
Ratio of 6th graders to 7th graders = 5 : 4
Let the number of graders be 5a and 4a
Number of 7th graders = 12
So , 4a = 12
a = 12/4 = 3
Number of 6th graders = 5×3 = 15 ANS
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#BE BRAINLY
First you would start getting the denominators to the same number and you could do this by multiplying 9/10 by 4, and 7/8 by 5 to get the denominators to 40 and when you add the fractions you get 71/40 so the answer would be D. About 2