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1 year ago

On Monday, a bakery sold 67 dozen cookies. How many total cookies did the bakery sell?

Mathematics

2 answers:

gulaghasi [49]1 year ago

8 0

Answer:

804

Step-by-step explanation:

dozen means 12

67 times 12 is 804

Andrews [41]1 year ago

7 0

In this problem, we need to use multiplication to find the answer

Since we know that the bakery sold 67 dozen cookies on Monday and a dozen means 12, we need to multiply 67 and 12. We get:

67 × 12 = 804

Hope this helps :)

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Answer:

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3 years ago

X 1 2 3 4 y 5 10 15 20 What's the constant?

DiKsa [7]

Answer:

x ---> 1

y ---> 5

Step-by-step explanation:

We are given paired values for two variables x and y and we are to determine the constant number by which each term is increased such that they are in a proportional relationship.

For x, we have the following paired values:

$x: 1, 2, 3, 4$

So here the difference between each consecutive term is 1 so the constant is 1.

And for y, we have:

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3 years ago

The volunteers at a high school football team’s concession stand are trying to decide on the price of the hot dogs they are sell

olga55 [171]

Answer:

x is the number of $1 increase in the price.

If there is no increase, then the total money earned is

2 × 70 = 140

If there is $1 increase, then the total money earned is

(2 + 1) × [70 - 8(1)]

If there is $2 increase, then the total money earned is

(2 + 2) × [70 - 8(2)]

If we continue the pattern, for x times $1 increase, total money earned is

(2 + x)(70 - 8x) =

If we substitute x = 0 in the above equation, we will get

the total money earned = $140.

It means if there is no increase, then the total money earned = 140.

Hence, 140 is the constant term and it represents that there is no increase in price.

Still stuck? Get 1-on-1 help from an expert tutor now.

Step-by-step explanation:

6 0

2 years ago

Find maclaurin series

Mumz [18]

Recall the Maclaurin expansion for cos(x), valid for all real x :

$\displaystyle \cos(x) = \sum_{n=0}^\infty (-1)^n \frac{x^{2n}}{(2n)!}$

Then replacing x with √5 x (I'm assuming you mean √5 times x, and not √(5x)) gives

$\displaystyle \cos\left(\sqrt 5\,x\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt5\,x\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^{2n}}{(2n)!}$

The first 3 terms of the series are

$\cos\left(\sqrt5\,x\right) \approx 1 - \dfrac{5x^2}2 + \dfrac{25x^4}{24}$

and the general n-th term is as shown in the series.

In case you did mean cos(√(5x)), we would instead end up with

$\displaystyle \cos\left(\sqrt{5x}\right) = \sum_{n=0}^\infty (-1)^n \frac{\left(\sqrt{5x}\right)^{2n}}{(2n)!} = \sum_{n=0}^\infty (-5)^n \frac{x^n}{(2n)!}$