Question

Which of these is a point-slope equation of the line that is perpendicular to y-3=4(x-10) and passes through (-3,7)?

Answer 1

Answer:

B

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=7$. We can find the slope which is perpendicular to the slope of 4 in the equation y=4(x-10). Perpendicular slope is the negative reciprocal which is -1/4.

We write  

$(y-7)=-\frac{1}{4}(x--3)\\(y-7)=-\frac{1}{4}(x+3)$