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3 years ago

Which of these is a point-slope equation of the line that is perpendicular to y-3=4(x-10) and passes through (-3,7)?

Mathematics

1 answer:

melomori [17]3 years ago

6 0

Answer:

Step-by-step explanation:

The point slope form of a line is $(y-y_1)=m(x-x_1)$ where $x_1=-3\\y_1=7$ . We can find the slope which is perpendicular to the slope of 4 in the equation y=4(x-10). Perpendicular slope is the negative reciprocal which is -1/4.

We write

$(y-7)=-\frac{1}{4}(x--3)\\(y-7)=-\frac{1}{4}(x+3)$

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2 years ago

What is the following sum 3b^2

densk [106]

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= $3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})$

We know that: $\sqrt[3]{27} = 3$

Similarly we also can simplify: $\sqrt[3]{b^6} = b^2$

So our expression will look like this:

= $3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})$

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Blababa [14]

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Step-by-step explanation:

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