All categories

2 years ago

Riddle: What is seen in the middle of March and April that can’t be seen at the beginning or end of either month?

Mathematics

2 answers:

iVinArrow [24]2 years ago

8 0

Answer: The letter R

Step-by-step explanation: I remember this when i was a child xd

Oxana [17]2 years ago

3 0

Answer:

The letter R

Step-by-step explanation:

maRch.......apRil

You might be interested in

<img src="https://tex.z-dn.net/?f=-3a%2B8%3D14%3D" id="TexFormula1" title="-3a+8=14=" alt="-3a+8=14=" align="absmiddle" class="l

Bess [88]

$a = - 2$

Step-by-step explanation:

1) Subtract 8 from both sides.

$- 3a = 14 - 8$

2) Simplify 14 - 8 to 6.

$- 3a = 6$

3) Divide both sides by, -3.

$a = - \frac{6}{3}$

4) Simplify 6/3 to 2.

$a = - 2$

Therefor, the answer is, a = -2.

8 0

3 years ago

Which expression is equivalent to 2 (-12r - 3) + (42 - })?

lara [203]

Answer:

362 is equivalent to ur answer

4 0

2 years ago

The power generated by an electrical circuit (in watts) as a function of its current ccc (in amperes) is modeled by: P(c)=-20(c-

alekssr [168]

Answer:

The current that produces maximum power is 3A

Step-by-step explanation:

Given

$P(c) = 20(c - 3)^2$

Required [Missing from the question]

The current that produces maximum power

First, we represent the function in standard form

$P(c) = 20(c - 3)^2$

$P(c) = 20(c - 3)(c - 3)$

Open bracket

$P(c) = 20(c^2 -6c+ 9)$

$P(c) = 20c^2 -120c+ 180$

The maximum value of c is:

$Max(c) = \frac{-b}{2a}$

Where:

$f(x) = ax^2 + b^2 + c$

By comparison: $P(c) = 20c^2 -120c+ 180$

$a = 20$

$b = -120$

$c = 180$

So, we have:

$Max(c) = \frac{-b}{2a}$

$Max(c) = \frac{-(-120)}{2 * 20}$

$Max(c) = \frac{120}{40}$

$Max(c) = 3$

5 0

3 years ago

A pack of red pens can be divided into equal shares among 3, 5, 6 and 9 teachers with no pen left over?

Ugo [173]

Answer:

90 red pens

Step-by-step explanation:

we need to find the least common multiple of the numbers 3 , 5 , 6 , 9

6 = 2 × 3

9 = 3²

then

LCM(3,5,6,9) = 2×5×3² = 2×5×9 = 90

The number 90 can be divided into 3 ,5 ,6 ,9 with no remainder

Therefore the pack must have 90 pens or a multiple of 90

For example 180 , 270 ...

7 0

2 years ago

<img src="https://tex.z-dn.net/?f=6%20%5Ctimes%20x%20%3D%20%20-%2024" id="TexFormula1" title="6 \times x = - 24" alt="6 \times

Finger [1]

The missing number is 4

8 0

3 years ago