Answer:
I think they would be 7 4/6 & 5 2/8
Step-by-step explanation:
srry if im late!
For this case we have the following system of equations:
Equating both equations we have:
We must find the solutions, for this we factor. We look for two numbers that, when multiplied, result in 4 and when added, result in 5. These numbers are 4 and 1:
Then, the factorized equation is of the form:
Thus, the solutions are:
We look for solutions for the variable "y":
Thus, the system solutions are given by:
ANswer:
Answer:
k = (6/15)
Step-by-step explanation:
The equation is:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
To have no solutions, we need to have something like:
x + 7 = x + 4
where we can remove x in both sides and end with
7 = 4
So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.
First, let's try to simplify our equation:
6*(x + 1) + 2 = 3*(k*5*x + 1) + 3
6*x + 6 + 2 = 3*k*5*x + 3*1 + 3
6*x + 8 = 15*k*x + 6
if 15*k = 6, then the system clerly has no solution.
then:
k = 6/15
then we get:
6*x + 8 = (6/15)*15*x + 6
6*x + 8 = 6*x + 6
8 = 6
The system has no solutions.
Answer:
B, because it's pretty much 3+ and 3- so in result 0
Answer:
An ordinary annuity is a series of equal payments made at the end of consecutive periods over a fixed length of time. The opposite of an ordinary annuity is an annuity due, in which payments are made at the beginning of each period.
Step-by-step explanation:
