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lozanna [386]
2 years ago
9

For what value of k does the equation 6(x + 1) + 2 = 3(k5x + 1) + 3 have no solution?

Mathematics
1 answer:
NARA [144]2 years ago
8 0

Answer:

k = (6/15)

Step-by-step explanation:

The equation is:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

To have no solutions, we need to have something like:

x + 7 = x + 4

where we can remove x in both sides and end with

7 = 4

So this equation is false, meaning that there is no value of x such that this equation is true, then the equation has no solutions.

First, let's try to simplify our equation:

6*(x + 1) + 2 = 3*(k*5*x + 1) + 3

6*x + 6 + 2 = 3*k*5*x + 3*1 + 3

6*x + 8 = 15*k*x + 6

if 15*k = 6, then the system clerly has no solution.

then:

k = 6/15

then we get:

6*x + 8 = (6/15)*15*x + 6

6*x + 8 = 6*x + 6

8 = 6

The system has no solutions.

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Answer number 1 please.​
Minchanka [31]

\sf {a}^{2}  =  {13}^{2}  -  {5}^{2}

Formula :

Base²= Hypotenuse² - Perpendicular ²

\\  \\

\hookrightarrow\sf {a}^{2}  =  {13}^{2}  -  {5}^{2}

\\  \\

\hookrightarrow\sf {a}^{2}  =169 - 25

\\  \\

\hookrightarrow\sf {a}^{2}  =144

\\  \\

\hookrightarrow\sf {a} = \sqrt{144}

\\  \\

\hookrightarrow\sf {a} = \sqrt{12 \times 12}

\\  \\

\hookrightarrow\sf {a} = 12

Remember the a² in formula has nothing to do with the a we have to find. :)

6 0
2 years ago
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3 years ago
PLS HELP Find the m∠RLU.<br> A. 10º<br> B. 6º<br> C. 25º<br> D. 50º
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3 years ago
I need Help!!!! Please Solve and show WORK!!!<br> 3(x+2)=15
ludmilkaskok [199]

Answer: x=3

Step-by-step explanation: First we do distributive property in the parentheses. Next we subtract both sides by 6. Lastly we divide both sides by 3. Algebraic Rules!!!

Work:

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Answer:

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BC=6.32

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AD6.32

Step-by-step explanation:

6 0
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