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4 years ago

12

Which integers between square 30 and square 40

rt{x}" alt="\sqrt{x}" align="absmiddle" class="latex-formula">

2 answers:

Maslowich4 years ago

8 0

65 and 2 so explanation I really want some points

anygoal [31]4 years ago

7 0

Answer:

6

Step-by-step explanation:

The only integer whose square is between 30 and 40 is 6.

30 < x^2 < 40.

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Please answer asap. NO SCAM LINKS.

solong [7]

B is the answer I did that last week at my school

4 0

3 years ago

aleksley [76]

Answer:

उत्तर:

गोलाको आयतन :4851 cm³

⁴/3 πr³=4851

r³=4851×3×7/(22*4)

r³=1157.625

r= $\sqrt[3]{1157.625}$

r=10.5

अब

गोलाको व्यास=2×r=10.5*2=21cm.

5 0

3 years ago

Is it possible to have a triangle such that none of the exterior angles is obtuse? Please help and explain

PolarNik [594]

Answer: No, it is not possible

A triangle can only have 1 obtuse interior angle, leaving the exterior angle next to it to be acute. For example, if you have an interior angle of 120 (obtuse) then the adjacent exterior angle is 60 (acute)

The other two interior angles must be acute if you go with 1 obtuse angle, which leaves the corresponding exterior angles to be obtuse. If you wanted the exterior angles to be all acute, then you would need 3 obtuse interior angles, but that is not possible.

Why isn't it possible to have 3 obtuse angles? Consider a triangle with interior angles A, B, C. The three angles must add to 180

A+B+C = 180

If A,B,C were all larger than 90, then

A > 90

B > 90

C > 90

A+B+C > 90+90+90

A+B+C > 270

but that contradicts A+B+C being equal to 180

6 0

4 years ago

Suppose that Eitan rolls a fair six-sided die and a fair four-sided die simultaneously. Let A be the event that the sum of the d

murzikaleks [220]

Answer:

Step-by-step explanation:

Part A

Let's see what the total ways of eight might be.

Dice (6 sides) Dice (4 sided)

6 2 You can't reverse them

5 3 You can't reverse these either.

4 4 You can't have a meaningful reversal.

That looks like all there is. So what's the universe of this set?

6 * 4 is the total number of combinations.

You have 3 that work.

P(A) = 3/24 = 1/8 = 0.125

=====================

Part B

There are 4 sets of doubles. As you can see, there is not 2 creations, so the answer is

P(B) = 4/24 = 1/6 = 0.1667

=================

Part C

P(A + B) = only 1 instance (4,4)

1/24 = 0.04167

======================

No they are not independent. They can both happen.

4 0

3 years ago

Read 2 more answers

Perform the indicated operation. (12x2 + 7y3)(4x2 + 7y3)

Verdich [7]

ANSWER

$48 {x}^{4} + 60{x}^{2} {y}^{3} + 56 {y}^{6}$

EXPLANATION

We want expand:

$(12x^2+8y^3)(4x^2+7y^3)$

We expand using the distributive to obtain:

$12 {x}^{2} (4 {x}^{2} + 7 {y}^{3} ) + 8 {y}^{3} (4 {x}^{2} + 7 {y}^{3} )$

$48 {x}^{4} + 28 {x}^{2} {y}^{3} + 32{x}^{2} {y}^{3} + 56 {y}^{6}$

Simplify further by combining the two terms in the middle:

$48 {x}^{4} + 60{x}^{2} {y}^{3} + 56 {y}^{6}$

4 0

4 years ago

Read 2 more answers