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Masja [62]
3 years ago
13

Write 35/13 as a mixed number is

Mathematics
2 answers:
umka2103 [35]3 years ago
6 0

Answer:  2  9/13

Step-by-step explanation:

to create a mixed fraction, you have to multiply the denominator by the whole number and add the numerator, in this problem you need to find the numbers to write 35/13. That is how I came up with my answer

Korolek [52]3 years ago
4 0

Answer:2 9/13

Step-by-step explanation:see attachment

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Find the midpoint of the 2 points (-2,-7) (10-5)
Inessa05 [86]

Answer:

(4,-6)

Step-by-step explanation:

3 0
3 years ago
Plz help me well mark brainliest if correct!!....
True [87]

Answer:

B) Fifth Grade Boys

Step-by-step explanation:

The far right green line represents the fifth grade boys, and you can see that this lines up right in the middle of 50 and 60.

8 0
2 years ago
Please help. Full explanation if you can.
sukhopar [10]
392 boots. If you divide everything into "sets" of an unknown amount, there are 5 more "sets" of boots than sandals, also known as the 245 boots. So if you divide 245 by 5, you'll get the number of items in a "set". Then just multiply by 8 from the 8:3 ratio. If you check it, it will come out to 392 boots to 147 sandals, which I think is ridiculous since sandals are supposed to come in pairs so  you should never have a odd number. But anyway, 392 - 147 = 245
6 0
3 years ago
Brent is a researcher for a food company. He is on a team creating a reduced-calorie version of its flagship cracker. The team w
Andre45 [30]

Answer:

Step-by-step explanation:

Hello!

The research team created a cracker with fewer calories. The average content of calories of the new crackers per serving of 6 should be less than 60.

To test it a random sample of 26 samples of the new cracker was taken and the calories per serving were measured.

Then the study variable is

X: calories of a 6 serve sample of the new reduced-calorie version. (cal)

The variable has a normal distribution with a population standard deviation of 0.82 cal.

To test the claim that the new crackers have on average less than 60 calories, the parameter of interest is the population mean (μ) and the hypotheses are:

H₀: μ ≥ 60

H₁: μ < 60

α: 0.01

Since the variable has a normal distribution and the population variance is known, the best statistic to use to conduct the test is a Standard Normal

Z= \frac{(X[bar]-Mu)}{\frac{Sigma}{\sqrt{n}}  } ~N(0;1)

This test is one tailed to the left, wich means that the null hypothesis will be rejected at low levels of the statistic.

Z_{\alpha } = Z_{0.01} = -2.334

If Z ≤ -2.334, the decision is to reject the null hypothesis.

If Z > -2.334, the decision is to not reject the null hypothesis.

Using the data of the sample I've calculated the sample mean.

X[bar]= ∑X/n= 1548.61/26= 59.56 cal

Z_{H_0}= \frac{(59.56-60)}{\frac{0.82}{\sqrt{26} } } = -2.736

The observed Z value is less than the critical value, so the decision is to reject the null hypothesis.

At a level of significance of 1%, you can conclude that the population mean of calories of the samples of new crackers is less than 60 cal.

I hope it helps!

6 0
3 years ago
Solve for x<br><br> 0.25x=10
Ad libitum [116K]
X=40 hope this helps nig
7 0
3 years ago
Read 2 more answers
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