Answer:
30
Step-by-step explanation:
x=6
4 by 6 =24
24 + 6 =30
Answer:
<h2>2/5</h2>
Step-by-step explanation:
The question is not correctly outlined, here is the correct question
<em>"Suppose that a certain college class contains 35 students. of these, 17 are juniors, 20 are mathematics majors, and 12 are neither. a student is selected at random from the class. (a) what is the probability that the student is both a junior and a mathematics majors?"</em>
Given data
Total students in class= 35 students
Suppose M is the set of juniors and N is the set of mathematics majors. There are 35 students in all, but 12 of them don't belong to either set, so
|M ∪ N|= 35-12= 23
|M∩N|= |M|+N- |MUN|= 17+20-23
=37-23=14
So the probability that a random student is both a junior and social science major is
=P(M∩N)= 14/35
=2/5
0.20(150) = 30 basketballs were in the shipment. Since the shipment presumably comprised only footballs and basketballs, the remainder of the shipment must consist of footballs.
150 - 30 = 120 footballs were in the shipment.
1. $325 2. $315,000 3.$2,600 4.$6,00 5.i don’t know
