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torisob [31]
3 years ago
7

Points Q and P on the coordinate grid below show the positions of two midfield players of a soccer team:

Mathematics
1 answer:
Ilya [14]3 years ago
8 0

Answer:

give a explanatio

Step-by-step explanation:

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What is 56.78 to one significant figure
Tasya [4]

Answer:

60.

Step-by-step explanation:

The second digit is 6, so we round up the first digit and add training zero. There is no need to add the '00' after the decimal point.

6 0
2 years ago
Test the claim below about the mean of the differences for a population of paired data at the level of significance α Assume the
Evgen [1.6K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The  correct option is F

t =  1.17

t_ {\alpha , df} =t_ {0.10 , 8} = 1.86

Since the test statistics<u> is outside </u>the rejection region , <u>we fail to reject </u>the null hypothesis ,There<u> is no</u>  statistically significant evidence to reject the claim

Step-by-step explanation:

From the question we are told that

    The  claim is  \mu =  0

Hence  

      The  null hypothesis is  H_o  :  \mu = 0

       The  alternative is  H_a  :  \mu  \ne  0

Generally the test statistics is mathematically represented as  

                 t =  \frac{\= d - \mu_d }{ \frac{s_d}{ \sqrt{n} } }

=>              t =  \frac{3.5 -0 }{ \frac{8.94}{ \sqrt{9} } }

=>              t =  1.17

Generally the degree of freedom is mathematically represented as

      df  =  n- 1

      df  =  9 -  1

      df  =  8

From the student t-distribution table  the critical value of  \alpha at a degree of freedom of  8 is  

          t_ {\alpha , df} =t_ {0.10 , 8} = 1.86

Since the t_ {\alpha , df} is  outside the rejection region , we fail to reject the null hypothesis ,There is no sufficient evidence to reject the claim

4 0
4 years ago
The average high temperature was 86° in august then 93° in September. What is the percent increase or decrease
SSSSS [86.1K]
The increase was 7 degrees
6 0
2 years ago
Which function's graph is shown below?
Makovka662 [10]
Go on desmos dot com; it lets you graph equations. Graph those and see which matches your picture.
6 0
4 years ago
4. Elena va a una fiesta pero no sabe que ponerse, así que lanza un moneda y un dado al
taurus [48]

Answer:

  • <u>1/4</u>

Explanation:

Hola. Puesto que tu pregunta está en español, te responderé en el mismo lenguage.

Estas son las posibilidades dadas por la combinación moneda/dado

                                      Número de combinaciones

Moneda: prenda

    Cara: vestido                 1 de 2:          1/2

     Sello: falda                    1 de 2:          1/2

Dado: color

    Par: negro                      3 de 6:          3/6

    Impar: café                     3 de 6:         3/6

En total son 2 × 6 resultados: 12 (incluye resultados repetidos, no son todos diferentes entre sí)

¿Cuántas combinaciones tienen vestido y color negro?

  • P(Vestido∩negro) = ?

Es decir: moneda = cara y dado = par

  • Son 1 × 3 = 3.

Por tanto, la probabilidad de vestido negro es:

  • 3 de 12 = 3/12 = 1/4 ← respuesta

Hay otras formas de resolverlo. Por ejemplo;

Como los resultados de lanzar la moneda y el dado son independientes:

  • P(Vestido∩negro) = P(Vestido) × P(Negro)
  • P(Vestido) = 1/2
  • P(Negro) = 3/6 = 1/2
  • P(Vestido) × P(Negro) = 1/2 × 1/2 = 1/4 ← mismo resultado
8 0
4 years ago
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