Yeah I don’t know but have someone else
USE CYMATH TO FIGURE THAT OUT
Answer:
L=6x^2-4x+5
P=12x^2-4x-2
Step-by-step explanation:
A=WL
So, we know the area is 6x^2-8x-30 and the width is 2x-6
Substitute
(6x^2-8x-30)=(2x-6)(L)
L=(6x^2-8x-30)/(2x-6
Divide
L=6x^2-4x+5
P=2L+2W
Substitute
P=2(6x^2-4x+5)+2(2x-6)
P=12×^2-8x+10+4x-12
Simplify
P=12x^2-4x-2
Answer:
y = 9x
Step-by-step explanation:
If you plug in the point into each equation, you get:
y = 1/9x
18 = 1/9 * 2
18 = 2/9
not true
y = 18x
18 = 18 * 2
18 = 36
not true
y = 9x
18 = 9 * 2
18 = 18
true, so this is the answer
y = 2x
18 = 2 * 2
18 = 4
not true
The problem does not say anything about how many of the marbles are yellow but if you put the first one back in the bag then it is an independent probability and each one would be the same individual probability. Since the problem doesn't say and I don't know if you have it somewhere else, I'll do it as an example.
Let's say there were 6 of the 10 marbles were yellow. So the probability of the first one is 6/10 and so is the second one 6/10. To find the total probability you multiply them together 6/10*6/10=36/100=9/25
Hope that helps. If you can tell me how many yellow there are I will show the work for the specific problem.
