a to C would be 4 3/4 + 2/3
3/4 + 2/3 = 9/12 + 8/12 = 17/12 = 1 5/12
1 5/12 + 4 = 5 5/12 total distance
You found CD from the Pythagorean theorem to be ...
... CD = √(5² -2²) = √21
Since triangle ADC ~ triangle ACB, the ratios of corresponding sides are the same:
... AC/AD = AB/AC
... AB = AC²/AD
... AB = 5²/2 = 12.5 . . . . . . . the base of the overall triangle
_____
Then the area (A) is ...
... A = (1/2)bh
... A = (1/2)(12.5)(√21) ≈ 28.64 square units
_____
As you see here, the altitude of a right triangle divides it into three similar triangles. From smallest to largest, they are ...
... ADC ~ CDB ~ ACB
You can figure this using AAA similarity, since the smallest and largest triangles listed above share an acute angle vertex (∠A). That, together with the right angle, means all angles are congruent. After that, then you know ∠ACD ≅ ∠CBD, so you can show the middle sized triangle is similar to the other two.
Answer:
1: 105 degrees
2: 75 degrees
Step-by-step explanation:
2 is a corresponding angle with 75.
1 is supplementary so x+75 = 180
x=105
10560 is the answer for this
