Answer:
0.0918
Step-by-step explanation:
We know that the average amount of money spent on entertainment is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The mean and standard deviation of average spending of sample size 25 are
μxbar=μ=95.25
σxbar=σ/√n=27.32/√25=27.32/5=5.464.
So, the average spending of a sample of 25 randomly-selected professors is normally distributed with mean=μ=95.25 and standard deviation=σ=27.32.
The z-score associated with average spending $102.5
Z=[Xbar-μxbar]/σxbar
Z=[102.5-95.25]/5.464
Z=7.25/5.464
Z=1.3269=1.33
We have to find P(Xbar>102.5).
P(Xbar>102.5)=P(Z>1.33)
P(Xbar>102.5)=P(0<Z<∞)-P(0<Z<1.33)
P(Xbar>102.5)=0.5-0.4082
P(Xbar>102.5)=0.0918.
Thus, the probability that the average spending of a sample of 25 randomly-selected professors will exceed $102.5 is 0.0918.
Answer:
5'4" or 64 inches
Step-by-step explanation:
<span>it is 21.4285714286 but you can just put it as 21.42
</span>
First, find 25% of 49.95. Turn 25% into a decimal by dividing by 100.
25% ⇒ 0.25
Now, multiply 0.25 by 49.95.
0.25 × 49.95 = 12.46
25% of 49.95 is 12.46, so subtract 12.46 from 49.95.
49.95 - 12.46 = 37.49
<h2>Answer:</h2>
<u>The discounted price of the jacket is </u><u>$37.49</u><u>.</u>
Now find 8% of 37.49.
8% ⇒ 0.08
Multiply 0.08 by 37.49.
0.08 × 37.49 = 2.99
<h2>Answer:</h2>
<u>The tax is </u><u>$2.99</u><u>.</u>
To find the full price, add 37.49 and 2.99 together.
37.49 + 2.99 = 40.48
<h2>Answer:</h2>
<u>The final cost is </u><u>$40.48</u><u>.</u>
Hey there!
1.
If Jessica found 3/6 of her money, half of it is still missing.
This is because 3/6 = 1/2, so Jessica also found half of her money and is missing half of it.
2.
16 ounces = 1 pound
16 ounces * 10 pounds = 160 <------
If the baby weighs 10 pounds, he weighs 160 ounces.
Hope this helps you.
Have a great day!
