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2 years ago

A car dealer's markup on every car they sell is 20%. For what price did the dealership buy a car that they sold for $18,600?

Mathematics

1 answer:

elena-s [515]2 years ago

8 0

Answer:

buying price = $15,500

Step-by-step explanation:

selling price 20% more than the buying price

let the buying price be 100% then;

selling price = 120%

120% = $18,600

100% = ?

(100 × 18600) ÷ 120

= $15,500

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Alexeev081 [22]

Answer:

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Step-by-step explanation:

The given quadratic equation is

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Group the constant terms on the right hand side.

$5x^2-7x=0-2$

$5x^2-7x=-2$

Divide through by 5.

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Add the square of half the coefficient of x., which is $(\frac{1}{2}\times- \frac{7}{5})^2=\frac{49}{100}$ to both sides of the equation.

$x^2-\frac{7}{5}x+\frac{49}{100}=-\frac{2}{5}+\frac{49}{100}$

The left hand side is now a perfect square.

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Take the square root of both sides;

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$x-\frac{7}{10}=\pm \frac{3}{10}$

$x=\frac{7}{10}\pm \frac{3}{10}$

$x=\frac{7-3}{10}$ or $x=\frac{7+3}{10}$

$x=\frac{4}{10}$ or $x=\frac{10}{10}$

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