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Please give brainliest !!!
Please give brainliest !!!
In triangle △JKL, ∠JKL is right angle, and KM is an altitude. JK=24 and JM=18, find JL.
1 answer:
Answer:
JL = 32
Step-by-step explanation:
We are told in the above question that:
In triangle △JKL, ∠JKL is right angle, and KM is an altitude. JK=24 and JM=18, find JL.
From the attached diagram, we can see that
JL : JK = JK: JM
Therefore,
JL/ JK = JK /JM
Where JL = Unknown
JK = 24
JM = 18
JL/ 24 = 24/18
Cross Multiply
24 × 24 = JL × 18
Divide both sides by 18
JL = (24 × 24) /18
JL = 576/18
JL = 32
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Answer:
34cm²
Step-by-step explanation:
Find diagram in the attached file.
Since each square on the grid represent 1cm², the length of the each square will be 1cm
Area of the irregular shape can be gotten by breaking the irregular shape into three shapes which are the triangle, rectangle and a parallelogram.
Area of the irregular shape = area of triangle + area of rectangle + area of parallelogram
For TRIANGLE
Area of triangle = 1/2×base×height
Since the base of triangle is on 4square grid,
Base = 4cm
Height = 2cm
Area = 1/2×4×2
Area of ∆ = 4cm²
FOR RECTANGLE
Area of rectangle = Length ×Breadth
Length = 3cm
Breadth = 5cm
Area of the rectangular shape = 3×5
= 15cm²
FOR PARALLELOGRAM
Area of a parallelogram = Base × Height
Base = 5cm
Height = 3cm
Area = 5cm×3cm
Area = 15cm²
Area of the irregular shape = 4cm²+15cm²+15cm²
=34cm²
