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Lisa [10]
3 years ago
7

Please answer please :)

Mathematics
2 answers:
KatRina [158]3 years ago
8 0
First one is 32.2 and the second one is -32.34
Licemer1 [7]3 years ago
4 0
39.4 + (-7.2) = 32.2

3.9 - 36.24 = -32.24

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While watching a football game, Jordan decided to list yardage gained as positive integers and yardage lost as negative integers
koban [17]

Answer:

There is a loss of 2 yards.

Step-by-step explanation:

To find the overall gain or loss, we add or subtract there values.

Initially, we have 0 yards.

Records 14, so 0 + 14 = 14, that is, for now a gain of 14

Then loses 7, so 14 - 7 = 7, for now a gain of 7.

Then, 7 - 9 = - 2, so in all, there is a loss of 2 yards.

3 0
3 years ago
A fish tank has 35 gallons of water in it, but suddenly starts leaking. Water is leaking from the tank at a rate of 1/4 gallon p
Norma-Jean [14]

Answer:

35 - m

Step-by-step explanation:

A tank containing 35 gallons of water is leaking at a rate of gallon per minute.

"m" represents the number of minutes spent

Number of gallons left in the tank = initial amount of water present – leaked amount of water

Number of gallons of water left = 35 gallons – number of minutes spent  rate of leakage.

Number of gallons of water left = 35 gallons – m minutes  1 gallons per minute

8 0
3 years ago
The product of two numbers is 192. what is the minimum value of the sum of the first value plus twice the second value
VARVARA [1.3K]
Let x and y be the two positive numbers. -  Their product is 192: x *  y  =  192   equation 1

-  the sum of the first plus twice the second is a minimum:  x + 2y

<span>From the first equation, y =  192 / x. 
Substitute that into the second equation:
</span>
 x + 2y = x + 2(<span>192/x ) = x + 384/x

</span>f(x) is minimum when f'(x) = 0 and f"(x) > 0 

f(x)= <span>x + 384/x
</span>
f(x) = 1-384/x^2 

<span>1-384  / x^2 =  0 

x^2-384 = 0 

x^ 2= 354
 x = radical  354    = 18.8  here i'm confused why the number is decimal
???/ 
</span>

4 0
3 years ago
The region bounded by y=x^2+1, y=x, x=-1, x=2 with square cross sections perpendicular to the x-axis.
VLD [36.1K]

Answer:

The bounded area is 5 + 5/6 square units. (or 35/6 square units)

Step-by-step explanation:

Suppose we want to find the area bounded by two functions f(x) and g(x) in a given interval (x1, x2)

Such that f(x) > g(x) in the given interval.

This area then can be calculated as the integral between x1 and x2 for f(x) - g(x).

We want to find the area bounded by:

f(x) = y = x^2 + 1

g(x) = y = x

x = -1

x = 2

To find this area, we need to f(x) - g(x) between x = -1 and x = 2

This is:

\int\limits^2_{-1} {(f(x) - g(x))} \, dx

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx

We know that:

\int\limits^{}_{} {x} \, dx = \frac{x^2}{2}

\int\limits^{}_{} {1} \, dx = x

\int\limits^{}_{} {x^2} \, dx = \frac{x^3}{3}

Then our integral is:

\int\limits^2_{-1} {(x^2 + 1 - x)} \, dx = (\frac{2^3}{2}  + 2 - \frac{2^2}{2}) - (\frac{(-1)^3}{3}  + (-1) - \frac{(-1)^2}{2}  )

The right side is equal to:

(4 + 2 - 2) - ( -1/3 - 1 - 1/2) = 4 + 1/3 + 1 + 1/2 = 5 + 2/6 + 3/6 = 5 + 5/6

The bounded area is 5 + 5/6 square units.

3 0
3 years ago
Finish the sequence of 10 numbers 26,37,48
9966 [12]

Answer:    37

Step-by-step explanation:

6 0
2 years ago
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