We have:
3x + 4y = 12
The first thing we should do in this case is clear and.
We have then:
4y = -3x + 12
y = (- 3x + 12) / (4)
Rewriting:
y = (- 3/4) x + 3
We evaluate now for x = 4
y = (- 3/4) (4) + 3
y = -3 + 3
y = 0
The ordered pair is:
(x, y) = (4, 0)
Answer:
y = (- 3/4) x + 3
(x, y) = (4, 0)
Cos(A-B) = cosAcosB + sinAsinB
<span>
cos(</span>π/2 - θ) = cos(π/2)cosθ + sin(π/2)sinθ
π/2 = 90°
cos(π/2) = cos90° = 0. sin(π/2) = sin90° = 1
cos(π/2 - θ) = cos(π/2)cosθ + sin(π/2)sin<span>θ
</span>
= 0*cosθ + 1*sin<span>θ = </span>sin<span>θ
Therefore </span>cos(π/2 - θ) = sin<span>θ
QED </span>
Where’s the question I need to see the problem
The answer is
96%.
Explanation:
It is generally presumed that the scores are normally distributed.
1) You are given how many standard deviations from the mean Jeremy's score is. This is exactly the definition of the
z-score. Therefore z = 1.75
2) Look at a left-tail z-table in order to find the area of the normal curve on the left of your z-score (see picture attached). A = 0.9599
3) Multiply the area by 100 in order to find the
percentile:
<span>0.9599 </span>× 100 = 95.99
Therefore, 95.99% of the students scored less than Jeremy.
Hence, the answer is
96%.