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Naily [24]
3 years ago
9

Please help with these problems! Will mark answer as brainliest and give 30 points. You have to show your work for each problem.

Mathematics
1 answer:
gulaghasi [49]3 years ago
4 0

Answer:

1) (2x + 2)(x + 2)

2)  2(x + 1)(x - 1)

3) (x^2 + 3)(x^2 - 3)

4) 2x(x + 5)(x - 2)

5) (5x + 2y)(5x - 2y)

Step-by-step explanation:

1)

2x^2 + 6x + 4

= 2x^2 + 4x + 2x + 4

= 2x(x + 2) + 2(x + 2)

= (2x + 2)(x + 2)

2)

2x^2 - 2

= 2(x^ 2 - 1) (The difference of two squares)

= 2(x + 1)(x - 1)

3)

x^4 - 9 (The difference of two squares)

=(x^2 + 3)(x^2 - 3)

4)

2x^3 + 6x^2 - 20x

= 2x(x^2 + 3x - 10)

= 2x(x + 5)(x - 2)

5)

25x^2 - 4y^2         (The difference of two squares)

= (5x + 2y)(5x - 2y)

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3 years ago
Match its group with its percentage or mean Using
krok68 [10]

(1)

Mean length of all fish in the sample - \boxed{\sf{\red{6.2}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 3 + 5 + 8 + 2 + 10 + 9 + 4 + 4)/(10)

= 62/10

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(2)

Mean length of adult fish in the sample - \boxed{\sf{\red{8.75}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (12 + 5 + 8 + 10)/(4)

= 35/4

=<em> 8.75</em>

(3)

Mean length of juvenile fish in the sample - \boxed{\sf{\red{4.5}}}

<u>Mean</u> = (Sum of observations)/(Number of observations)

= (5 + 3 + 2 + 9 + 4 + 4)/(6)

= 27/6

<em>= 4.5</em>

(4)

Percentage of sample that were adult fish - \boxed{\sf{\red{40}}}

<u>Percentage</u> = (No. of adult fishes)/(Total no. of fishes) × 100

% = (4/10) × 100

<em>% = 40</em>

(5)

Percentage of sample that were juvenile fish - \boxed{\sf{\red{60}}}

<u>Percentage</u> = (No. of juvenile fishes)/(Total no. of fishes) × 100

% = (6/10) × 100

<em>% = </em><em>6</em><em>0</em>

(6)

Percentage of sample that were juveniles over 8 inches long - \boxed{\sf{\red{10}}}

<u>Percentage</u> = (No. of juveniles over 8 inches)/(Total no. of fishes) × 100

% = (1/10) × 100

<em>% = </em><em>1</em><em>0</em>

7 0
3 years ago
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