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Dima020 [189]
3 years ago
5

What are the subsets of red blue and yellow

Mathematics
1 answer:
DiKsa [7]3 years ago
3 0

green orange and purple


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Find the solution to the system of equations y=x-4 and y=4x+2
dmitriy555 [2]

The answer is y=x-4=4x+2

7 0
3 years ago
Read 2 more answers
What are the explicit equation and domain for an arithmetic
max2010maxim [7]

Given:

First term of an arithmetic sequence = 5

Second term = 3

To find:

The explicit formula for the given arithmetic sequence.

Solution:

We have,

First term: a_1=5

Second term: a_2=3

Common difference is

d=a_2-a_1

d=3-5

d=-2

Now, the explicit formula for an arithmetic sequence is

a_n=a+(n-1)d

where, a is first term and d is common difference.

Putting a=5 and d=-2, we get

a_n=5+(n-1)(-2)

It can also be written as

a_n=5-2n+2

a_n=7-2n

Here, n is an integer greater than or equal to 1.

Domain is the set of input values.

Therefore, the explicit equation is a_n=5+(n-1)(-2) or a_n=7-2n and domain is all interest greater than or equal to 1.

8 0
2 years ago
A jewelry store has 9/10 of an ounce of gold they need to split into one 6 ounce groups how many groups going to make
Mariana [72]
12
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12
12
12
12
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1

12
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4 0
3 years ago
A square with side x is changing with time where x(t)=3t+1. What is rate of change of the area of the square when t=2 seconds.
GuDViN [60]

Answer:

Rate of change of the area of the square is 42 units at t = 2.

Step-by-step explanation:

We note that the area of the square is given by: A(x) = x^2 but we aim to find \frac{dA}{dt}. But we can use the chain rule to pull out that dA/dt. Doing so gives us:

\frac{dA}{dt} = \frac{dA}{dx} \times \frac{dx}{dt}.

Now, \frac{dA}{dx} = 2x (by the power rule and \frac{dx}{dt} = 3.

But since we have "x" and not "t", we want to find what x is when t = 2. Substituting t = 2 gives us x(2) = 3(2) + 1 = 7.

So, finally, we see that:

\frac{dA}{dt} = 2(7) \times 3 = 14 \times 3 = 42.

7 0
3 years ago
what is the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube
Dmitrij [34]
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

\frac{99}{2} (2x+98)=p^3 \\  \\ 99x+4,851=p^3\\ \\ \Rightarrow x=\frac{p^3-4,851}{99}

By substitution, we have that p=33 and x=314.

Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
3 0
3 years ago
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