Question

Find the solution of this system of equations 2x-4y=32 2x-8y=48

Answer 1

2x - 4y = 32
2x - 8y = 48

2x - 2x - 4x - (-8y) = 32 - 48

4x = -16
x = -16 ÷ 4
x = -4

substitute your value of x into any of the original equations

2 (-4) - 4y = 32

-8 - 4y = 32

-4y = 32 + 8

-4y = 40
y = 40 ÷ -4
y = -10