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Sergio039 [100]
3 years ago
6

Anyone good at Linear Equations and Intercepts if so please help. This stuff makes me feel stupid.

Mathematics
1 answer:
Anettt [7]3 years ago
6 0
If I can offer a suggestion ... You ought to look back in your book, or notes,
or homework, and recall what "intercept" means, and what one looks like.

The "y-intercept" of an equation is the point where
the graph crosses the y-axis.
On this graph, the line crosses the y-axis at y=5 .

The "x-intercept" of an equation is the point where
the graph crosses the x-axis.
On this graph, the line never crosses the x-axis at all.
(That DOESN't mean the x-intercept is zero.  It means there isn't any.)

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Answer:

Option B.  The equation has a maximum value with a y-coordinate of -21.

Step-by-step explanation:

The correct quadratic equation is

y=-3x^{2}+12x-33

This is a vertical parabola open downward (the leading coefficient is negative)

The vertex represent a maximum

Convert to vertex form

Factor -3

y=-3(x^{2}-4x)-33

Complete the square

y=-3(x^{2}-4x+2^2)-33+12

y=-3(x^{2}-4x+4)-21

Rewrite as perfect squares

y=-3(x-2)^{2}-21

The vertex is the point (2,-21)

therefore

The equation has a maximum value with a y-coordinate of -21

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