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Bingel [31]
3 years ago
15

Money is borrowed at 14% simple interest. After one year, $1249.44 pays off the loan. How much was originally borrowed? I got $1

096 for the amount of the original loan, but I'm not sure if to right.
Mathematics
1 answer:
WITCHER [35]3 years ago
8 0
The formula is
A=p (1+rt)
A future value 1249.22
P present value ?
R interest rate 0.14
T time 1 year
We need to solve for p
P=A÷(1+rt)
P=1,249.22÷(1+0.14×1)
P=1,095.81 round your answer
P=1096

Hope it helps
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Answer:

66 feet

Step-by-step explanation:

30+30=30 feet

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12*3=36

30+36=66

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Can someone help! I know the answer I just need step by step!
baherus [9]

Answer:

4 \sqrt{2}

Step-by-step explanation:

Rewrite 32 as the product of 16 and 2:

\implies \sqrt{32}=\sqrt{16 \cdot 2

Apply exponent rule \sqrt{a \cdot b}=\sqrt{a}\sqrt{b}

\implies \sqrt{16 \cdot 2}=\sqrt{16}\sqrt{2}

Rewrite 16 as 4²:

\implies \sqrt{16}\sqrt{2}=\sqrt{4^2}\sqrt{2}

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\implies \sqrt{4^2}\sqrt{2}=4 \sqrt{2}

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2 years ago
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https://www.rcboe.org/cms/lib/GA01903614/Centricity/Domain/1351/21.2%20permutations%20and%20probability.pdf

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What is 2 and 6/7 times 4/5
bulgar [2K]

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Step-by-step explanation:

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4 0
3 years ago
A flat circular plate has the shape of the region x squared plus y squared less than or equals 1.The​ plate, including the bound
rjkz [21]

Answer:

We have the coldest value of temperature T(\frac{3}{4},0) = -9/16. and the hottest value is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

Step-by-step explanation:

We need to take the derivative with respect of x and y, and equal to zero to find the local minimums.

The temperature equation is:

T(x,y)=x^{2}+2y^{2}-\frac{3}{2}x

Let's take the partials derivatives.

T_{x}(x,y)=2x-\frac{3}{2}=0

T_{y}(x,y)=4y=0

So, we can find the critical point (x,y) of T(x,y).

2x-\frac{3}{2}=0

x=\frac{3}{4}

4y=0

y=0

The critical point is (3/4,0) so the temperature at this point is: T(\frac{3}{4},0)=(\frac{3}{4})^{2}+2(0)^{2}-(\frac{3}{2})(\frac{3}{4})

T(\frac{3}{4},0)=-\frac{9}{16}    

Now, we need to evaluate the boundary condition.

x^{2}+y^{2}=1

We can solve this equation for y and evaluate this value in the temperature.

y=\pm \sqrt{1-x^{2}}

T(x,\sqrt{1-x^{2}})=x^{2}+2(1-x^{2})-\frac{3}{2}x  

T(x,\sqrt{1-x^{2}})=-x^{2}-\frac{3}{2}x+2

Now, let's find the critical point again, as we did above.

T_{x}(x,\sqrt{1-x^{2}})=-2x-\frac{3}{2}=0            

x=-\frac{3}{4}    

Evaluating T(x,y) at this point, we have:

T(-(3/4),\sqrt{1-(-3/4)^{2}})=-(-\frac{3}{4})^{2}-\frac{3}{2}(-\frac{3}{4})+2  

T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}

Now, we can see that at point (3/4,0) we have the coldest value of temperature T(\frac{3}{4},0) = -9/16. On the other hand, at the point -(3/4),\frac{\sqrt{7}}{4}) we have the hottest value of temperature, it is T(-(3/4),\frac{\sqrt{7}}{4})=\frac{5}{16}.

I hope it helps you!

4 0
2 years ago
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