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OleMash [197]
3 years ago
8

PLZ PLZ PLZ PLZ PLZ PLZ PLZ HELP!!!!!

Mathematics
2 answers:
umka2103 [35]3 years ago
7 0

Answer:

i would say all equilateral traingles are acute triangles.

Step-by-step explanation:

Oksanka [162]3 years ago
5 0

Answer:

equal

Step-by-step explanation:

just read

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Find the missing side of the triangle, leave answer in simplest radical form.
OLga [1]

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<h3>x =  \sqrt{15^{2}-13^{2}</h3>

Step-by-step explanation:

3 0
3 years ago
May I have some help please.
anzhelika [568]

Answer:

Step-by-step explanation:

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2 years ago
At 2:00 PM a car's speedometer reads 30 mi/h. At 2:20 PM it reads 50 mi/h. Show that at some time between 2:00 and 2:20 the acce
Bad White [126]

Answer:

Let v(t) be the velocity of the car t hours after 2:00 PM. Then \frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }.  By the Mean Value Theorem, there is a number c such that 0 < c with v'(c)=60 \:{\frac{mi}{h^2}}. Since v'(t) is the acceleration at time t, the acceleration c hours after 2:00 PM is exactly 60 \:{\frac{mi}{h^2}}.

Step-by-step explanation:

The Mean Value Theorem says,

Let be a function that satisfies the following hypotheses:

  1. f is continuous on the closed interval [a, b].
  2. f is differentiable on the open interval (a, b).

Then there is a number c in (a, b) such that

f'(c)=\frac{f(b)-f(a)}{b-a}

Note that the Mean Value Theorem doesn’t tell us what c is. It only tells us that there is at least one number c that will satisfy the conclusion of the theorem.

By assumption, the car’s speed is continuous and differentiable everywhere. This means we can apply the Mean Value Theorem.

Let v(t) be the velocity of the car t hours after 2:00 PM. Then v(0 \:h) = 30 \:{\frac{mi}{h} } and v( \frac{1}{3} \:h) = 50 \:{\frac{mi}{h} } (note that 20 minutes is 20/60=1/3 of an hour), so the average rate of change of v on the interval [0 \:h, \frac{1}{3} \:h] is

\frac{v(1/3)-v(0)}{1/3-0}=\frac{50 \:{\frac{mi}{h} }-30\:{\frac{mi}{h} }}{1/3\:h-0\:h} = 60 \:{\frac{mi}{h^2} }

We know that acceleration is the derivative of speed. So, by the Mean Value Theorem, there is a time c in (0 \:h, \frac{1}{3} \:h) at which v'(c)=60 \:{\frac{mi}{h^2}}.

c is a time time between 2:00 and 2:20 at which the acceleration is 60 \:{\frac{mi}{h^2}}.

4 0
3 years ago
A scuba diver swimming at the Deppe shown, and then swim 0.5 feet toward the surface every three seconds. What is the location o
ivanzaharov [21]
For every 3 seconds, the scuba diver dives 0.5 feet
after 15 seconds = your answer

3 x 5 = 15
0.5 x 5 = your answer

your answer = 2.5

2.5 is your answer

hope this helps
7 0
3 years ago
Please help!
Marat540 [252]

Answer:

y= 3(x+5)^2 -4

5 0
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