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nataly862011 [7]
4 years ago
9

A spherical balloon is inflated so that its volume is increasing at the rate of 3.1 {\rm ft}^3{\rm /min}. how rapidly is the dia

meter of the balloon increasing when the diameter is 1.6 feet?
Mathematics
1 answer:
liberstina [14]4 years ago
7 0
<span>The volume is represented by V = volume of sphere = (4/3) π r³ = (4/3) π (D/2)³ = π D³ / 6 dV / dt = (π D² / 2) dD/dt ft³/min dV/dt = 2.3 ft³/min πD²/2 dD/dt = 2.3 dD/dt = 4.6 / (πD²) ft/min Thus when D = 1.4 ft dD / dt = 4.6 / ( π 1.4² ) ft/min = 0.7471 ft/min</span>
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Step-by-step explanation:

A regression analysis was performed to determine if there is a relationship between the happiness index (y) and life expectancy in years of a given country (x).

The output of the regression analysis are as follows:

a = -0.762

b = 0.119

r² = 0.8649

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(A)

The equation of the Least Squares Regression line of the form y = _ + _ x is:

y=-0.762+0.119x

(B)

The correction between the variables happiness index (y) and life expectancy in years of a given country (x) is, 0.93.

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Thus, if a country increases its life expectancy, the happiness index will increase.

(C)

Compute the value of y for x = x + 3.5 as follows:

y=-0.762+0.119x

  =-0.762+0.119\times (x+3.5)\\\\=(-0.762+0.119x)+0.4165\\\\=y+0.4165

Thus, if the life expectancy is increased by 3.5 years in a certain country, the happiness index will increase by 0.4165.

(D)

Compute the value of y for x = 67 as follows:

y=-0.762+0.119x

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Thus, if the life expectancy is 67 years in a certain country, the happiness index will be 7.21.

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