Answer:
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Answer:
9/2 or 4.5
Step-by-step explanation:
15/4x6/5 = 3/2x3 = 9/2
a. What percent of people earn less than $40000?
Solution: Let S be the random variable of a salary of employee (in $), S ~ N(50000,20000). Then the random
variable X =−50000
20000
~N(0,1).
( < 40000) = ( <
40000 − 50000
20000 ) = ( < −0.5) = (−0.5) = 0.3085375.
Here Φ(x) denotes the cumulative distribution function of a standard normal distribution.
Answer: 31%.
b. What percent of people earn between $45000 and $65000?
Solution:
(45000 < < 65000) = (
45000 − 50000
20000 < <
65000 − 50000
20000 ) = (−0.25 < < 0.75)
= (0.75) − (−0.25) = 0.7733726 − 0.4012937 = 0.3720789.
Answer: 37%.
c. What percent of people earn more than $70000?
Solution:
( > 70000) = ( >
70000 − 50000
20000 ) = ( > 1) = 0.8413447.
Answer: 84%.
What is the MAD of 82, 72, 45, 91, 58, 83, 65, 87, 90, 77, 73, 89 ?<br>
I'm very confused.
dsp73
MAD= mean absolute deviation. Find the mean first. So if you add all the numbers and divide by the amount of numbers. Then you do the data value subtracted by the mean. Mean= 912 divided by 12 which equals 76. 912-76= 836. Sorry if it’s wrong, I don’t remember much from learning this.
