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Anettt [7]
3 years ago
10

Solve the system by elimination 2x+6y= -12 5x-5y= -10

Mathematics
2 answers:
kvv77 [185]3 years ago
5 0
First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier. 
Eliminate 'x' variable by subtracting 2nd equation from 1st.

   x + 3y = -6
-(x  - y = 2)
----------------------
       4y  = -8

Solve for 'y'
4y = -8

y = (-8)/4 = -2


Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

Lena [83]3 years ago
3 0

B) (0,-2) I got 100% right.

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Classify the equation, 7x+6=7x-5, as having one solution, no solution, or infinitely many solutions.
Ksenya-84 [330]

Answer:

Step-by-step explanation:

7x + 6 = 7x - 5

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What is the definition of marginal​ utility? A. The average utility from consuming a good or service multiplied by the number of
Ilya [14]

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3 years ago
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DanielleElmas [232]
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4 0
3 years ago
Read 2 more answers
Let a, n, b, r, and k be integers. If a = nb+r and k|a and k|b, then k|r
Kryger [21]

Answer:

Proof for k|r

Step-by-step explanation:

We are given that a, n, b, r and k are integers.

Also,

a = nb + r

Since k divides a and b, we can write,

a = rk and b = sk, where r and s are integers.

Now, we have to prove that k divides r as well that is k|r

Putting value of a and b in the equation, we get:

rk = n(sk) + r\\r = rk - nsk\\r = (r-sn)k

Since, (r-sn) is an integer, k divides r.

5 0
3 years ago
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