Solve the system by elimination 2x+6y= -12 5x-5y= -10

2 answers:

5 0

First thing you should do is reduce coefficients.

1st equation has all multiples of '2'. Divide by 2
---> x +3y = -6

2nd equation has multiples of 5. Divide by 5.
---> x - y = 2

Now elimination part is easier.
Eliminate 'x' variable by subtracting 2nd equation from 1st.

x + 3y = -6
-(x - y = 2)
----------------------
4y = -8

Solve for 'y'
4y = -8

y = (-8)/4 = -2

Substitute value for 'y' back into 2nd equation:
x - (-2) = 2
x + 2 = 2
x = 0

Solution to system is:
x=0, y =-2

Lena [83]3 years ago

3 0

B) (0,-2) I got 100% right.

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