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MAVERICK [17]
4 years ago
5

△ABC∼△DEF , △ABC has a height of 14 centimeters, and △DEF has a height of 6 centimeters. What is the ratio of the area of △ABC t

o the area of △DEF ?

Mathematics
2 answers:
Kamila [148]4 years ago
8 0
Since triangle ABC is similar to triangle DEF then the ratio of the corresponding sides is constant.
The ratio of the corresponding lengths is referred to as the linear scale factor.
Considering the heights of the two triangles;
L.S.F = 14/6
          = 7/3
The ratio in area (A.S.F) is given by (L.S.F)²
Therefore, A.S.F = (7/3)² = 49/9
Thus te ratio of the area of triangle ABC to DEF is 49:9
Minchanka [31]4 years ago
5 0

Answer:

49:9

Step-by-step explanation:

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A blimp can be seen flying at an altitude of 5500 feet above a motor speedway during a race. The slanted distance directly to th
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Answer:

The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}

Step-by-step explanation:

Given as :

The distance of blimp  (AB) = 5500 feet

The slanted distance to the pagoda (BC) = d feet

The horizontal distance (AC) = h

Let the angle made between slanted distance and horizontal distance be Ф

So , cos Ф = \frac{AC}{BC} = \frac{h}{d}

And sin Ф =  \frac{AB}{BC} = \frac{5500}{d}

∵, cos²Ф = 1 - sin²Ф

So, (\frac{h}{d})^{2} = 1 - (\frac{5500}{d})^{2}

Or, (\frac{h}{d})^{2} = (\frac{d^{2}- 5500^{2}}{d^{2}})

Or,                                     h² = d² - 5500²

∴                                        h = \sqrt{d^{2}- 5500^{2}}

Or,                                     h = \sqrt{(d + 5500) (d - 5500)}

Hence The expression of h as function of x is   h = \sqrt{(d + 5500) (d - 5500)}     Answer

3 0
4 years ago
Only number 6. ‍ ‍ ‍ ‍ ‍ ‍ ‍
djverab [1.8K]
The answer is 6, 4 divided by 2/3 =6
if you need to show your work just multiply by the reciprocal :)
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Answer:

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Step-by-step explanation:

The expanded form of (a+b)³ is ...

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When we are expanding (x +3)³, the x-term is ...

  3(x)(3²) = 27x

The coefficient of x in the expansion is 27.

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