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Anettt [7]
3 years ago
13

1A technical magazine stated that the mean retail cost of all models of a particular laptop was $600. A random sample of 10 stor

es that sell that laptop in Los Angeles found it sold with a mean cost of $ 586.50 and a standard deviation of $26.77. Does this indicate that the mean cost of that laptop in Los Angeles is less than $ 600
Mathematics
1 answer:
My name is Ann [436]3 years ago
3 0

Answer:

Yes

Step-by-step explanation:

Given,

Population mean Z = 600

Sample mean, µ = 586.50

Size of the sample, n = 10

Standard deviation, σ = 26.77

The testing hypothesis is,

Null hypothesis = µ<600

Alternative hypothesis = µ≥600

The test statistics is the calculated value of Z,

(Z- µ)/(σ/√n)

= (600-586.50)/(26.77/√10)

= (13.5*3.1623)/26.77

= 42.691/26.77

= 1.5947

And at 5% level of significance, the table value of Z = 1.644

Here, calculated Z<Table value of Z, so we accept the null hypothesis.

So, the null hypothesis is accepted. The mean value of the laptop is less than 600.

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Move the numbers to the table to arrange them in order from least to greatest.
777dan777 [17]

Answer:

-3/5

-1/2

-0.4

0.6

4/5

Step-by-step explanation:

For this question I converted the fractions to decimals.

-3/5 = -0.6

-1/2 = -0.5

4/5 = 0.8

Start off with the negatives, as they are the lowest numbers. <em>The further they are from zero the lower they get.</em>

-0.6  (-3/5)

-0.5  (-1/2)

-0.4

Now there are only <em>2</em> positive numbers, so order them.

0.6

0.8 (4/5)

Put it all together:

-3/5

-1/2

-0.4

0.6

4/5

3 0
3 years ago
Given the function f(x) = 5^x, Section A is from x = 0 to x = 1 and Section B is from x = 2 to x = 3. Part A: Find the average r
Wewaii [24]
Table of the graph:
x: <em></em>1  2    3 
y: 5  25  125

Average Rate of Change = \frac{y_{2}-y_{1} }{x_{2} -  x_{1} }

Section A = 25-5/2-1 =20/1 =20
Section B = 125 - 25/ 3-2 = 100/1 = 100

So, Section B is 5 times greater than A.
Section B is greater because the slope of two points is greater than points in Section A.
8 0
3 years ago
Pls explain your answer
spayn [35]

Yo sup??

this is of the form called slope and point... hence

y-11=-4(x+2)

therefore the correct answer is option A

Hope this helps

8 0
3 years ago
Determine the astm grain size number if 33 grains per square inch are measured at a magnification of 270×
strojnjashka [21]
8.9

The equation for the grain size is expressed as the equality:
Nm(M/100)^2 = 2^(n-1)
where
Nm = number of grains per square inch at magnification M.
M = Magnification
n = ASTM grain size number

Let's solve for n, then substitute the known values and calculate.
Nm(M/100)^2 = 2^(n-1)

log(Nm(M/100)^2) = log(2^(n-1))
log(Nm) + 2*log(M/100) = (n-1) * log(2)
(log(Nm) + 2*log(M/100))/log(2) = n-1
(log(Nm) + 2*log(M/100))/log(2) + 1 = n

(log(33) + 2*log(270/100))/log(2) + 1 = n
(1.51851394 + 2*0.431363764)/0.301029996 + 1 = n
(1.51851394 + 0.862727528)/0.301029996 + 1 = n
2.381241468/0.301029996 + 1 = n
7.910312934 + 1 = n
8.910312934 = n

So the ASTM grain size number is 8.9

If you want to calculate the number of grains per square inch, you'd use the
same formula with M equal to 1. So:
Nm(M/100)^2 = 2^(n-1)
Nm(1/100)^2 = 2^(8.9-1)
Nm(1/10000) = 2^7.9
Nm(1/10000) = 238.8564458
Nm = 2388564.458

Or about 2,400,000 grains per square inch.
7 0
3 years ago
BIOLOGY
kozerog [31]

Answer:

Step-by-step explanation:

Types of Angle Pairs

Adjacent angles: two angles with a common vertex, sharing a common side and no overlap.

Adjacent Angles

Angles ∠1 and ∠2 are adjacent.

Complementary angles: two angles, the sum of whose measures is 90°.

Complementary Angles

Angles ∠1 and ∠2 are complementary.

Complementary are these angles too(their sum is 90°):

Complementary Angles

Supplementary angles: two angles, the sum of whose measures is 180°.

Supplementary Angles

Angles ∠1 and ∠2 are supplementary.

 

Angle pairs formed by parallel lines cut by a transversal

When two parallel lines are given in a figure, there are two main areas: the interior and the exterior.  

When two parallel lines are cut by a third line, the third line is called the transversal. In the example below, eight angles are formed when parallel lines m and n are cut by a transversal line, t.  

There are several special pairs of angles formed from this figure. Some pairs have already been reviewed:  

Vertical pairs:

∠1 and ∠4  

∠2 and ∠3  

∠5 and ∠8  

∠6 and ∠7  

Recall that all pairs of vertical angles are congruent.  

Supplementary pairs:

∠1 and ∠2  

∠2 and ∠4  

∠3 and ∠4  

∠1 and ∠3  

∠5 and ∠6  

∠6 and ∠8  

∠7 and ∠8  

∠5 and ∠7  

Recall that supplementary angles are angles whose angle measure adds up to 180°. All of these supplementary pairs are linear pairs. There are other supplementary pairs described in the shortcut later in this section. There are three other special pairs of angles. These pairs are congruent pairs.

Alternate interior angles two angles in the interior of the parallel lines, and on opposite (alternate) sides of the transversal. Alternate interior angles are non-adjacent and congruent.  

 

Alternate exterior angles two angles in the exterior of the parallel lines, and on opposite (alternate) sides of the transversal. Alternate exterior angles are non-adjacent and congruent.  

 

Corresponding angles two angles, one in the interior and one in the exterior, that are on the same side of the transversal. Corresponding angles are non-adjacent and congruent.  

 

Use the following diagram of parallel lines cut by a transversal to answer the example problems.  

 

Example:  

What is the measure of ∠8?  

The angle marked with measure 53° and ∠8 are alternate exterior angles. They are in the exterior, on opposite sides of the transversal. Because they are congruent, the measure of ∠8 = 53°.  

Example:  

What is the measure of ∠7?  

∠8 and ∠7 are a linear pair; they are supplementary. Their measures add up to 180°. Therefore, ∠7 = 180° – 53° = 127°.

1. When a transversal cuts parallel lines, all of the acute angles formed are congruent, and all of the obtuse angles formed are congruent.  

 

In the figure above ∠1, ∠4, ∠5, and ∠7 are all acute angles. They are all congruent to each other. ∠1 ≅ ∠4 are vertical angles. ∠4 ≅ ∠5 are alternate interior angles, and ∠5 ≅ ∠7 are vertical angles. The same reasoning applies to the obtuse angles in the figure: ∠2, ∠3, ∠6, and ∠8 are all congruent to each other.

2. When parallel lines are cut by a transversal line, any one acute angle formed and any one obtuse angle formed are supplementary.  

 

From the figure, you can see that ∠3 and ∠4 are supplementary because they are a linear pair.

Notice also that ∠3 ≅ ∠7, since they are corresponding angles. Therefore, you can substitute ∠7 for ∠3 and know that ∠7 and ∠4 are supplementary.

Example:  

In the following figure, there are two parallel lines cut by a transversal. Which marked angle is supplementary to ∠1?  

 

The angle supplementary to ∠1 is ∠6. ∠1 is an obtuse angle, and any one acute angle, paired with any obtuse angle are supplementary angles. This is the only angle marked that is acute.

4 0
3 years ago
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