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Gre4nikov [31]
2 years ago
12

Solving the equation 2x + 3(3x – 5) = 51 for x gives x =

Mathematics
2 answers:
mart [117]2 years ago
7 0

2x + 3(3x – 5) = 51

2x + 9x - 15 = 51

11x - 15 = 51

11x = 66

x = 6


answer

x = 6

Bond [772]2 years ago
6 0

Answer:

x = 6

Step-by-step explanation:

JUst took the test

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Greq and Sam oredered a pizza for lunch. Greg ate 3/4 of the pizza, and Sam ate 1/8 of the pizza. How much of the whoe pizza was
MatroZZZ [7]
Convert 3/4 to a denominator of 8 by multiplying by two, getting you:

6/8 + 1/8

Add those and you get D) 7/8
3 0
3 years ago
I’m not sure what to do..
Arlecino [84]

Answer:

x=291/76

Step-by-step explanation:

Convert:

1/2x(6x+ 1/2)=-0.8x+16-1.2

Remove parenthesis and move terms:

3x+1/4=-0.8x+14.8

Collect the like terms and convert:

3x+0.8x=14.8-1/4

Subtract the fractions:

3.8x=74/5-1/4

Divide both sides by 3.8:

3.8x=291/20

x=291/76

7 0
2 years ago
Solve the inequality and describe the solution set:<br> y-6 ≥ 12
Finger [1]
Y<span>≥18

You want to get the y only on one side of the equation. To get rid of the -6 you  have to add 6 to both sides to even out the equation.

y-6</span><span>≥</span><span>12
 +6 +6
y </span>≥18
3 0
3 years ago
Read 2 more answers
Carla is age 32. how many quarters of coverage does she need to be fully insured
never [62]
According to my research, And I would take this with a grain of salt since I am not a insurance rep . You can earn up to four quarters of coverage each year. In order to be fully insured for Social Security Disability purposes, you must have earned at least one quarter of coverage per year for each year since you turned 21 years old. A minimum of six quarters of coverage is needed to be fully insured at any age so maybe Six quarters, at least according to SSD .
Hope I helped or shed some light !.
7 0
3 years ago
Does someone mind helping me with this? Thank you!
zalisa [80]

\qquad\qquad\huge\underline{{\sf Answer}}

The given two polygons are similar to one another ~

Sides of the given polygons are in ratio of :

\qquad \sf  \dashrightarrow \: 28 : 4

to put in simple Ratio ~

\qquad \sf  \dashrightarrow \: 7: 1

So, the sides of the larger polygon are :

  • 4 × 7 = 28

  • 6 × 7 = 42

  • 3 × 7 = 21

  • 4 × 7 = 28

  • 7 × 7 = 49

  • 3 × 7 = 21

  • 3 × 7 = 21

  • 4 × 7 = 28

Now, to find the Perimeter of larger polygon ~ add the side length of all sides :

\qquad \sf  \dashrightarrow \:p = 28 + 42 + 21 + 28 + 49 + 21 + 21 + 28

\qquad \sf  \dashrightarrow \:238 \:  \: units

6 0
2 years ago
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