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Kobotan [32]
3 years ago
14

The heights of american men aged 18 to 24 are approximately normally distributed with a mean of 68 inches and standard deviation

of 2.5 inches. Half of all young men are shorter than?
how do I figure this out???
Mathematics
2 answers:
Rudik [331]3 years ago
7 0
A normal distribution is symmetrical about the mean. Therefore half of all young men are shorter than 68 inches.
elena55 [62]3 years ago
5 0
The given says the height distribution is normally distributed with the mean height equal to 68 inches. In this case, the bell-shaped curve has a vertical symmetry at 68 inches. This means, half of the mean exceeds 68 inches while the other half has height below 68 inches.
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Answer:

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Step-by-step explanation:

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2: Interchange the variables y and t, resulting in t=-\frac{8}{27}y^3

3: Multiply both sides by 27, resulting in 27t=-8y^3

4: Divide both sides by -8, resulting in -\frac{27t}{8}=y^3

5: Find the cube root of both sides, resulting in \sqrt[3]{-\frac{27t}{8} }=y

6: Apply a radical rule, resulting in -\sqrt[3]{\frac{27t}{8} } =y

7: Apply another radical rule, resulting in -\frac{\sqrt[3]{27t} }{\sqrt[3]{8} } =y

8: Simplify the denominator, resulting in  -\frac{\sqrt[3]{27t} }{2} =y

9: Apply yet another radical rule, resulting in -\frac{\sqrt[3]{27}\sqrt[3]{t}   }{2} =y

10: Simplify \sqrt[3]{27}, resulting in -\frac{3\sqrt[3]{t}   }{2} =y

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