Question

Solve for x 3 x − 8 ≤ 23 AND − 4 x + 26 ≥ 6 Please help thank you!!

Answer 1

To solve for x, you need to isolate/get the variable "x" by itself in the inequality:

3x - 8 ≤ 23       Add 8 on both sides

3x - 8 + 8 ≤ 23 + 8

3x ≤ 31         Divide 3 on both sides to get "x" by itself

$\frac{3x}{3} \leq \frac{31}{3}$

$x\leq \frac{31}{3}$     (x is any number less than or equal to 31/3)

-4x + 26 ≥ 6          Subtract 26 on both sides

-4x ≥ -20      Divide -4 on both sides [When you multiply/divide by a negative number to both sides of an inequality, you flip the sign </>]

$\frac{-4x}{-4} \geq \frac{-20}{-4}$   (two negative signs cancel each other out and become positive)

x ≤ 5     (x is any number less than or equal to 5)