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garik1379 [7]
4 years ago
12

To show the electron configuration for an atom, when would it be better to use an orbital notation than to use a written configu

ration with numbers, letters, and superscripts
Physics
2 answers:
fgiga [73]4 years ago
8 0

Answer:

The correct answer is how the electron distributes itself in shells

Explanation:

An orbital documentation is progressively fitting on the off chance that you need to demonstrate how the electrons of an iota are disseminated in each subshell. This is on the grounds that there are a few iotas that have unique electronic designs that aren't clear in simply composed setups.

To demonstrate the electron setup for an atom, it would be better to utilize an orbital documentation than to utilize a composed design with numbers, letter and superscripts when the point is to indicate orbital shapes in subshells.

Clarification : When we expect to demonstrate the orbital shapes in sub shells, it implies that we are meaning to demonstrate the electron turns for that component or atom. The images used to speak to electrons are these ↑↓ bolts. At the point when both the bolt are inverse way that implies it drops the turn of one another and is in unbiased state.

lakkis [162]4 years ago
5 0

when the aim is to show electron distributions in shells.

hope this helps :)

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Information about mars' moons.
Alex

Answer:

mars is a fourth planet of the sun and the second planet in the solar system

moon is a natural satellite of the earth it isthe fifth largest moon in the solar system

6 0
2 years ago
On March 21, a stick casts the following shadow. What is the most likely time of day?
jenyasd209 [6]

Answer:

9:00 AM

Explanation:

I took the test and that was the answer

5 0
4 years ago
Read 2 more answers
A police car moving at 36.0 m/s is chasing a speeding motorist traveling at 30.0 m/s. The police car has a siren that emits soun
maxonik [38]

Answer:

The frequency heard by the motorist is 4313.2 Hz.

Explanation:

let f1 be the frequency emited by the police car and f2 be the frequency heard by the motorist, let v1 be the speed of the police car and v2 be the speed of the motorist and v = 343 m/s be the speed of sound.

because the police car is moving towards the motorist at a higher speed, then the motorist will hear a increasing frequency and according to Dopper effect, that frequency is given by:

f1 =  [(v + v2/(v - v1))]×(f2)

   = [( 343 + 30)/(343 - 36)]×(3550)

   = 4313.2 Hz

Therefore, the frequency heard by the motorist is 4313.2 Hz.

5 0
3 years ago
A very long, straight wire carries a current of 19.0 A in the +k direction. An electron 1.9 cm from the center of the wire in th
Anestetic [448]

(a) 1.03\cdot 10^{-16} N, -k direction

First of all, let's find the magnetic field produced by the wire at the location of the electron:

B=\frac{\mu_0 I}{2 \pi r}

where

I = 19.0 A is the current in the wire

r = 1.9 cm = 0.019 m is the distance of the electron from the wire

Substituting,

B=\frac{(1.256\cdot 10^{-6})(19.0A)}{2 \pi (0.019 m)}=2\cdot 10^{-4} T

and the direction is +j direction (tangent to a circle around the wire)

Now we can find the force on the electron by using:

F=qvBsin \theta

where

q=1.6\cdot 10^{-19}C is the electron's charge

v=3.23\cdot 10^6 m/s is the electron speed

B=2\cdot 10^{-4} T is the magnetic field

\theta is the angle between the direction of v and B

In this case, the electron is travelling away from the wire, while the magnetic field lines (B) form circular paths around the wire: this means that v and B are perpendicular, so \theta=90^{\circ}, sin \theta=1. So, the force on the electron is

F=(1.6\cdot 10^{-19}C)(3.23\cdot 10^6 m/s)(2\cdot 10^{-4} T)(1)=1.03\cdot 10^{-16} N

The direction is given by the right hand rule:

- Index finger: direction of motion of the electron, +i direction (away from the wire)

- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)

- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means -k direction (anti-parallel to the current in the wire)

(b) 1.03\cdot 10^{-16} N, +i direction

The calculation of the magnetic field and of the force on the electron are exactly identical as before. The only thing that changes this time is the direction of the force. In fact we have:

- Index finger: direction of motion of the electron, +k direction (parallel to the current in the wire)

- Middle finger: direction of magnetic field, +j direction (tangent to a circle around the wire)

- Thumb: direction of the force --> since the charge is negative, the sign must be reversed, so it means +i direction (away from the wire)

(c) 0

In this case, the electron is moving tangent to a circle around the wire, in the +j direction. But this is exactly the same direction of the magnetic field: this means that v and B are parallel, so \theta=0, sin \theta=0, therefore the force on the electron is zero.

6 0
4 years ago
A store owner has 11 baskets of mangoes for sale at k8.26.How much will he receive in total when he sells them​
Grace [21]
11*2.86 which is 31.46
Hope this helps
8 0
4 years ago
Read 2 more answers
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